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Asivrs

  • 3 years ago

An engineer wanted to approximate the width, in feet of a river. she placed markers at point A and point B to represent the average width of the river. She also placed 3 other markers along the riverbank and measured the distances shown in the diagram below. Based on this diagram, what was the width of the river, in feet, from point A to point B?

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  1. Asivrs
    • 3 years ago
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    |dw:1337276808827:dw|

  2. atlas
    • 3 years ago
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    Use similarity of triangles

  3. atlas
    • 3 years ago
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    The two triangles that u see are similar and hence their corresponding sides will have the same ration

  4. Asivrs
    • 3 years ago
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    so..i should put 62 over 93 and 49 over X?

  5. Asivrs
    • 3 years ago
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    find the ratio after that then... times it by 2?

  6. atlas
    • 3 years ago
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    Label the two triangles and see which angles are equal................The sides corresponding to equal angles are proportional|dw:1337277341870:dw| here AB:AC = BE:CD

  7. atlas
    • 3 years ago
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    You do not know AB............So let it be x

  8. Asivrs
    • 3 years ago
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    but you dont know AD either.. right?

  9. atlas
    • 3 years ago
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    U do not need AD................The equation AB:AC = BE:CD can be written as x/(x+49)= 62/93 Solve for x (Remember x = AB)

  10. atlas
    • 3 years ago
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    |dw:1337277608429:dw|

  11. Asivrs
    • 3 years ago
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    \[\left[\begin{matrix}x & 62\\ x+49 & 93\end{matrix}\right]\]

  12. Asivrs
    • 3 years ago
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    like okay.. x + 49 = AC,, so... ugh sorry i dont get math easily

  13. Asivrs
    • 3 years ago
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    is there like a formula you can give me to help me out? i know if i see what i need to do i'll understand.

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