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lasttccasey Group Title

I need help solving for x.

  • 2 years ago
  • 2 years ago

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  1. lasttccasey Group Title
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    This is it:\[a^2x+(a-2)=(a+2)x\]Not sure where to start..

    • 2 years ago
  2. lasttccasey Group Title
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    I have the answer but I don't know how to get it:\[x=\frac{-1}{a+1}\]

    • 2 years ago
  3. math456 Group Title
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    \[a ^{2}x+a-2=ax+2x\] multiply them first then put all the a's to one side..

    • 2 years ago
  4. lasttccasey Group Title
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    Well I shouldn't say not sure where to start I guess.. I got: \[a(ax−x+1)=x(x+2)\]This is where I'm actually stuck at.

    • 2 years ago
  5. math456 Group Title
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    how about if we do.. \[a ^{2}x+a-2=ax+2x\]

    • 2 years ago
  6. math456 Group Title
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    \[a ^{2}x-a-ax=2x+2\] \[a ^{2}x-ax-2x=2-a\] \[x(a ^{2}-a-2)=2-a\]

    • 2 years ago
  7. math456 Group Title
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    here solve for x!!

    • 2 years ago
  8. math456 Group Title
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    x=2-a/a^2-a-2 -> factor the denominator a^2-a-2 x= - (-2+a)/(a+1)(a-2) x=-1/(a+1)

    • 2 years ago
  9. lasttccasey Group Title
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    Yea I had just tried that way before asking on here and didn't think about factoring the a^2-a-2 so thats where I stopped and tried a different way. Thanks though

    • 2 years ago
  10. math456 Group Title
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    welcome.. :)

    • 2 years ago
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