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lasttccasey

  • 3 years ago

I need help solving for x.

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  1. lasttccasey
    • 3 years ago
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    This is it:\[a^2x+(a-2)=(a+2)x\]Not sure where to start..

  2. lasttccasey
    • 3 years ago
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    I have the answer but I don't know how to get it:\[x=\frac{-1}{a+1}\]

  3. math456
    • 3 years ago
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    \[a ^{2}x+a-2=ax+2x\] multiply them first then put all the a's to one side..

  4. lasttccasey
    • 3 years ago
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    Well I shouldn't say not sure where to start I guess.. I got: \[a(ax−x+1)=x(x+2)\]This is where I'm actually stuck at.

  5. math456
    • 3 years ago
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    how about if we do.. \[a ^{2}x+a-2=ax+2x\]

  6. math456
    • 3 years ago
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    \[a ^{2}x-a-ax=2x+2\] \[a ^{2}x-ax-2x=2-a\] \[x(a ^{2}-a-2)=2-a\]

  7. math456
    • 3 years ago
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    here solve for x!!

  8. math456
    • 3 years ago
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    x=2-a/a^2-a-2 -> factor the denominator a^2-a-2 x= - (-2+a)/(a+1)(a-2) x=-1/(a+1)

  9. lasttccasey
    • 3 years ago
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    Yea I had just tried that way before asking on here and didn't think about factoring the a^2-a-2 so thats where I stopped and tried a different way. Thanks though

  10. math456
    • 3 years ago
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    welcome.. :)

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