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lasttccasey
 4 years ago
I need help solving for x.
lasttccasey
 4 years ago
I need help solving for x.

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lasttccasey
 4 years ago
Best ResponseYou've already chosen the best response.0This is it:\[a^2x+(a2)=(a+2)x\]Not sure where to start..

lasttccasey
 4 years ago
Best ResponseYou've already chosen the best response.0I have the answer but I don't know how to get it:\[x=\frac{1}{a+1}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[a ^{2}x+a2=ax+2x\] multiply them first then put all the a's to one side..

lasttccasey
 4 years ago
Best ResponseYou've already chosen the best response.0Well I shouldn't say not sure where to start I guess.. I got: \[a(ax−x+1)=x(x+2)\]This is where I'm actually stuck at.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how about if we do.. \[a ^{2}x+a2=ax+2x\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[a ^{2}xaax=2x+2\] \[a ^{2}xax2x=2a\] \[x(a ^{2}a2)=2a\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x=2a/a^2a2 > factor the denominator a^2a2 x=  (2+a)/(a+1)(a2) x=1/(a+1)

lasttccasey
 4 years ago
Best ResponseYou've already chosen the best response.0Yea I had just tried that way before asking on here and didn't think about factoring the a^2a2 so thats where I stopped and tried a different way. Thanks though
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