The figure below shows Quadrilateral CDBE inscribed in a circle with center A.
http://go.flvs.net/courses/1/flvs_57_3641_12676/ppg/respondus/pool_Geom_3641_1005_03/image0014e9880ac.gif

- anonymous

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- anonymous

The paragraph proof with missing statement proves that its opposite angles are supplementary. Which statement can be used to fill in the blank space?
Given that CDBE is a quadrilateral inscribed in a circle with center A, ∡DCE and ∡DBE are inscribed angles. Since the measure of an inscribed angle is one-half the measure of its intercepted arc, __________________________________
and ∡DBE is half of arc DCE. Since arc DBE and arc DCE add up to the whole circle, or 360 degrees, the total of ∡DCE and ∡DBE must be half of 360, or 180 degrees. Therefore, they are supplementary. By the definition of a quadrilateral, all interior angles must add to 360. Therefore, the other two angles must also be supplementary.
Answer
∡CBE is half of arc DCE
∡EDC is half of arc ECD
∡DCE is half of arc DBE
∡DBE is half of arc DCE

- anonymous

Did you get the answer to this?

- anonymous

hey yeahh sorry i dont remember if it was right or not tho hold on. did you still need the answer?

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## More answers

- anonymous

Yes. I'm working on that assignment right now, and would love some help. Thanks

- anonymous

The Circle Proof assignment.

- anonymous

ok i got all of those right so for this one the answer was --arc DBE and arc DCE

- anonymous

you got the all right? first time, i only got one

- anonymous

no aha i only got 2 right the first time i think the second time i used the first one to correct myself tho nd got them all right

- anonymous

and help you'd offer?

- anonymous

what about the one with the two-column proof with the circle?

- anonymous

asking which statement to be used to fill in the blank

- anonymous

lol well i got them all right the second time so i can help you as much as i can at least and the answer for that one i had as GK + GJ = JK

- anonymous

these are my answers:
GI = FI
GK = FI
AJ = AH
GH = FJ

- anonymous

##### 1 Attachment

- anonymous

mmmm idk post the question nd pic. i think our questions are kinda diff. cuz im going off of my second attempt so not all of them are exactly the same as thee questions for the first attempt so

- anonymous

i posted a picture of the question and answers above.

- anonymous

i see it now hold on

- anonymous

yeahh im not sure but i just asked for some help from this guy he is rlly good at this stuff so hopefully he can help some

- anonymous

Our charts should look the same, just have different pieces missing.

- anonymous

Well, yeah, but yours asks for the square root postulate, where as mine asked for the segment addition postulate.

- anonymous

if you had the segment addition postulate missing, it should have the square root postulate one already filled in with the answer i'm looking for

- anonymous

ooh duh sorry.... its GK = FI

- anonymous

okay one more

- anonymous

thank you very much by the way! you're such a good help :)

- anonymous

Alright, go ahead

- anonymous

Jennifer made the following measurements: CF = 8 cm, DF = 4 cm, EF = 7 cm and BF = 3 cm. The following proof shows that Jennifer’s measurements were wrong. What is the missing reason in the proof?

- anonymous

is this in the same assignment?

- anonymous

Yes.

- anonymous

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- anonymous

choices:
Multiplication Property of Equality
Simplify
Two Secants from the Same Point
Substitution

- anonymous

ok i see it .i had simplify to fill in for the blank next to 32 = 21

- anonymous

I'm looking for this one: 8 · 4 = 7 · 3

- anonymous

the one above 32=21

- anonymous

mmk it's substitution

- anonymous

ah thank you so much again! :)

- anonymous

aha np =)

- anonymous

you do FLVS too?

- anonymous

yep it's my first year though. i will be back in hs nxt yr i hope tho

- anonymous

i'll message you. :D

- anonymous

ok =D

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