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anonymous
 4 years ago
The figure below shows Quadrilateral CDBE inscribed in a circle with center A.
http://go.flvs.net/courses/1/flvs_57_3641_12676/ppg/respondus/pool_Geom_3641_1005_03/image0014e9880ac.gif
anonymous
 4 years ago
The figure below shows Quadrilateral CDBE inscribed in a circle with center A. http://go.flvs.net/courses/1/flvs_57_3641_12676/ppg/respondus/pool_Geom_3641_1005_03/image0014e9880ac.gif

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The paragraph proof with missing statement proves that its opposite angles are supplementary. Which statement can be used to fill in the blank space? Given that CDBE is a quadrilateral inscribed in a circle with center A, ∡DCE and ∡DBE are inscribed angles. Since the measure of an inscribed angle is onehalf the measure of its intercepted arc, __________________________________ and ∡DBE is half of arc DCE. Since arc DBE and arc DCE add up to the whole circle, or 360 degrees, the total of ∡DCE and ∡DBE must be half of 360, or 180 degrees. Therefore, they are supplementary. By the definition of a quadrilateral, all interior angles must add to 360. Therefore, the other two angles must also be supplementary. Answer ∡CBE is half of arc DCE ∡EDC is half of arc ECD ∡DCE is half of arc DBE ∡DBE is half of arc DCE

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Did you get the answer to this?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hey yeahh sorry i dont remember if it was right or not tho hold on. did you still need the answer?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes. I'm working on that assignment right now, and would love some help. Thanks

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The Circle Proof assignment.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok i got all of those right so for this one the answer was arc DBE and arc DCE

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you got the all right? first time, i only got one

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no aha i only got 2 right the first time i think the second time i used the first one to correct myself tho nd got them all right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and help you'd offer?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what about the one with the twocolumn proof with the circle?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0asking which statement to be used to fill in the blank

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol well i got them all right the second time so i can help you as much as i can at least and the answer for that one i had as GK + GJ = JK

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0these are my answers: GI = FI GK = FI AJ = AH GH = FJ

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0mmmm idk post the question nd pic. i think our questions are kinda diff. cuz im going off of my second attempt so not all of them are exactly the same as thee questions for the first attempt so

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i posted a picture of the question and answers above.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeahh im not sure but i just asked for some help from this guy he is rlly good at this stuff so hopefully he can help some

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Our charts should look the same, just have different pieces missing.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well, yeah, but yours asks for the square root postulate, where as mine asked for the segment addition postulate.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if you had the segment addition postulate missing, it should have the square root postulate one already filled in with the answer i'm looking for

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ooh duh sorry.... its GK = FI

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thank you very much by the way! you're such a good help :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Jennifer made the following measurements: CF = 8 cm, DF = 4 cm, EF = 7 cm and BF = 3 cm. The following proof shows that Jennifer’s measurements were wrong. What is the missing reason in the proof?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is this in the same assignment?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0choices: Multiplication Property of Equality Simplify Two Secants from the Same Point Substitution

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok i see it .i had simplify to fill in for the blank next to 32 = 21

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm looking for this one: 8 · 4 = 7 · 3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0mmk it's substitution

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ah thank you so much again! :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yep it's my first year though. i will be back in hs nxt yr i hope tho
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