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brinethery

  • 3 years ago

Find the matrix of the linear transformation T(f(t)) = f(2t+1) from P2 to P2 with respect to the basis B (script B) = (f1 = 1 +2t^2, f2=1, f3=t)

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  1. brinethery
    • 3 years ago
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    halp!

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  2. brinethery
    • 3 years ago
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    @No-data

  3. brinethery
    • 3 years ago
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    no-dataaaa!

  4. No-data
    • 3 years ago
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    It really doesn't

  5. No-data
    • 3 years ago
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    ??

  6. brinethery
    • 3 years ago
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    Fallingangel, don't ever take linear algebra. It is the worstest!

  7. brinethery
    • 3 years ago
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    @no-data see the pdf file.

  8. No-data
    • 3 years ago
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    ok

  9. No-data
    • 3 years ago
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    I think you need to apply the transformation to each vector of the basis.

  10. No-data
    • 3 years ago
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    and you form a matrix with the coefficients of the result in columns.

  11. brinethery
    • 3 years ago
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    So would the first vector in the basis for f1 be [1,0,2] because of the standard basis [1,x,x^2]?

  12. No-data
    • 3 years ago
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    I thought that is the way, but I'm checking. if its true.

  13. No-data
    • 3 years ago
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    Hmm what is the result of apply the transformation to the f_1 vector?

  14. No-data
    • 3 years ago
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    I got 3 + 8t + 8 t^2

  15. alexwee123
    • 3 years ago
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    ugh linear algebra o.0

  16. brinethery
    • 3 years ago
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    haha true alex. It's sht sh(((ts

  17. brinethery
    • 3 years ago
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    *the

  18. No-data
    • 3 years ago
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    \[T(f_1(t)) = f_1(2t+1)=1+2(2t+1)^2\]

  19. No-data
    • 3 years ago
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    I got \(3 + 8t + 8t^2\) am I right?

  20. brinethery
    • 3 years ago
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    sec... I think there's something more you have to do. Let me pull up some pages from a book.

  21. No-data
    • 3 years ago
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    Ok

  22. brinethery
    • 3 years ago
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    So it looks like you first have to plug 2t+1 into the x's in your standard P2 polynomial first.

  23. brinethery
    • 3 years ago
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    So you'll have 4t^2+4t+1

  24. No-data
    • 3 years ago
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    what is your standard polynomial?

  25. brinethery
    • 3 years ago
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    I guess I meant plug in 1 +2t^2 into our polynomial. 4(1+2t^2)^2 +4t +1 = 4(1+2t^2)(1+2t^2) +4t +1 =4(1 + 4t^2 +4t^4) +4t +1

  26. brinethery
    • 3 years ago
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    P2: ax^2 +bx +c

  27. brinethery
    • 3 years ago
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    See I'm really confused. I think I'm going to stop right there b/c I'm not on the right track I don't think.

  28. No-data
    • 3 years ago
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    You need to remember how to obtain the matrix of a transformation first.

  29. No-data
    • 3 years ago
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    Always go back to your definitions and well understood theorems brinethery.

  30. No-data
    • 3 years ago
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    Right now I don't remember well, and I don't have math books at work to help you as I wish. But I think that is the way.

  31. No-data
    • 3 years ago
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    take some rest if you need it.

  32. No-data
    • 3 years ago
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    are you allright?

  33. brinethery
    • 3 years ago
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    I'm fine, I just really need help to this question

  34. No-data
    • 3 years ago
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    Ok.

  35. brinethery
    • 3 years ago
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    How are you?

  36. No-data
    • 3 years ago
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    As I said you before, you just need to apply the transformation to each of the vectors of your basis. and form a matrix.

  37. No-data
    • 3 years ago
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    with the results aligned in columns.

  38. brinethery
    • 3 years ago
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    http://www.youtube.com/watch?v=Du84AF2VOWA&feature=related

  39. No-data
    • 3 years ago
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    I mean: \[\left[\begin{matrix} F^T(f_1(t))& F^T(f_2(t)) & F^T(f_3(t)) &\end{matrix}\right]\]

  40. No-data
    • 3 years ago
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    Sorry I can't see you tube videos at work. =(

  41. No-data
    • 3 years ago
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    it's blocked.

  42. brinethery
    • 3 years ago
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    That's okay

  43. No-data
    • 3 years ago
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    but what does it show the video?

  44. brinethery
    • 3 years ago
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    Argentine tango

  45. brinethery
    • 3 years ago
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    My goal in life is to travel to Buenos Aires and learn tango there

  46. No-data
    • 3 years ago
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    You mean one of the many goals on your life =P

  47. brinethery
    • 3 years ago
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    I have no other goals. If I could just dance then I would be happy lol

  48. No-data
    • 3 years ago
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    look for punk tango on you tube.

  49. No-data
    • 3 years ago
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    that is the tango i want to dance haha

  50. No-data
    • 3 years ago
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    well thank you brinethery.

  51. No-data
    • 3 years ago
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    I really miss math.. snif snif haha

  52. No-data
    • 3 years ago
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    see you!

  53. brinethery
    • 3 years ago
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    bye

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