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brinethery Group Title

Find the matrix of the linear transformation T(f(t)) = f(2t+1) from P2 to P2 with respect to the basis B (script B) = (f1 = 1 +2t^2, f2=1, f3=t)

  • 2 years ago
  • 2 years ago

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  1. brinethery Group Title
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    halp!

    • 2 years ago
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  2. brinethery Group Title
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    @No-data

    • 2 years ago
  3. brinethery Group Title
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    no-dataaaa!

    • 2 years ago
  4. No-data Group Title
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    It really doesn't

    • 2 years ago
  5. No-data Group Title
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    ??

    • 2 years ago
  6. brinethery Group Title
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    Fallingangel, don't ever take linear algebra. It is the worstest!

    • 2 years ago
  7. brinethery Group Title
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    @no-data see the pdf file.

    • 2 years ago
  8. No-data Group Title
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    ok

    • 2 years ago
  9. No-data Group Title
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    I think you need to apply the transformation to each vector of the basis.

    • 2 years ago
  10. No-data Group Title
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    and you form a matrix with the coefficients of the result in columns.

    • 2 years ago
  11. brinethery Group Title
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    So would the first vector in the basis for f1 be [1,0,2] because of the standard basis [1,x,x^2]?

    • 2 years ago
  12. No-data Group Title
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    I thought that is the way, but I'm checking. if its true.

    • 2 years ago
  13. No-data Group Title
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    Hmm what is the result of apply the transformation to the f_1 vector?

    • 2 years ago
  14. No-data Group Title
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    I got 3 + 8t + 8 t^2

    • 2 years ago
  15. alexwee123 Group Title
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    ugh linear algebra o.0

    • 2 years ago
  16. brinethery Group Title
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    haha true alex. It's sht sh(((ts

    • 2 years ago
  17. brinethery Group Title
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    *the

    • 2 years ago
  18. No-data Group Title
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    \[T(f_1(t)) = f_1(2t+1)=1+2(2t+1)^2\]

    • 2 years ago
  19. No-data Group Title
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    I got \(3 + 8t + 8t^2\) am I right?

    • 2 years ago
  20. brinethery Group Title
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    sec... I think there's something more you have to do. Let me pull up some pages from a book.

    • 2 years ago
  21. No-data Group Title
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    Ok

    • 2 years ago
  22. brinethery Group Title
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    So it looks like you first have to plug 2t+1 into the x's in your standard P2 polynomial first.

    • 2 years ago
  23. brinethery Group Title
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    So you'll have 4t^2+4t+1

    • 2 years ago
  24. No-data Group Title
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    what is your standard polynomial?

    • 2 years ago
  25. brinethery Group Title
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    I guess I meant plug in 1 +2t^2 into our polynomial. 4(1+2t^2)^2 +4t +1 = 4(1+2t^2)(1+2t^2) +4t +1 =4(1 + 4t^2 +4t^4) +4t +1

    • 2 years ago
  26. brinethery Group Title
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    P2: ax^2 +bx +c

    • 2 years ago
  27. brinethery Group Title
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    See I'm really confused. I think I'm going to stop right there b/c I'm not on the right track I don't think.

    • 2 years ago
  28. No-data Group Title
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    You need to remember how to obtain the matrix of a transformation first.

    • 2 years ago
  29. No-data Group Title
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    Always go back to your definitions and well understood theorems brinethery.

    • 2 years ago
  30. No-data Group Title
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    Right now I don't remember well, and I don't have math books at work to help you as I wish. But I think that is the way.

    • 2 years ago
  31. No-data Group Title
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    take some rest if you need it.

    • 2 years ago
  32. No-data Group Title
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    are you allright?

    • 2 years ago
  33. brinethery Group Title
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    I'm fine, I just really need help to this question

    • 2 years ago
  34. No-data Group Title
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    Ok.

    • 2 years ago
  35. brinethery Group Title
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    How are you?

    • 2 years ago
  36. No-data Group Title
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    As I said you before, you just need to apply the transformation to each of the vectors of your basis. and form a matrix.

    • 2 years ago
  37. No-data Group Title
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    with the results aligned in columns.

    • 2 years ago
  38. brinethery Group Title
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    http://www.youtube.com/watch?v=Du84AF2VOWA&feature=related

    • 2 years ago
  39. No-data Group Title
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    I mean: \[\left[\begin{matrix} F^T(f_1(t))& F^T(f_2(t)) & F^T(f_3(t)) &\end{matrix}\right]\]

    • 2 years ago
  40. No-data Group Title
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    Sorry I can't see you tube videos at work. =(

    • 2 years ago
  41. No-data Group Title
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    it's blocked.

    • 2 years ago
  42. brinethery Group Title
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    That's okay

    • 2 years ago
  43. No-data Group Title
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    but what does it show the video?

    • 2 years ago
  44. brinethery Group Title
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    Argentine tango

    • 2 years ago
  45. brinethery Group Title
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    My goal in life is to travel to Buenos Aires and learn tango there

    • 2 years ago
  46. No-data Group Title
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    You mean one of the many goals on your life =P

    • 2 years ago
  47. brinethery Group Title
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    I have no other goals. If I could just dance then I would be happy lol

    • 2 years ago
  48. No-data Group Title
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    look for punk tango on you tube.

    • 2 years ago
  49. No-data Group Title
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    that is the tango i want to dance haha

    • 2 years ago
  50. No-data Group Title
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    well thank you brinethery.

    • 2 years ago
  51. No-data Group Title
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    I really miss math.. snif snif haha

    • 2 years ago
  52. No-data Group Title
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    see you!

    • 2 years ago
  53. brinethery Group Title
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    bye

    • 2 years ago
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