Find the matrix of the linear transformation T(f(t)) = f(2t+1) from P2 to P2 with respect to the basis B (script B) = (f1 = 1 +2t^2, f2=1, f3=t)

- anonymous

- jamiebookeater

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

halp!

##### 1 Attachment

- anonymous

@No-data

- anonymous

no-dataaaa!

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

It really doesn't

- anonymous

??

- anonymous

Fallingangel, don't ever take linear algebra. It is the worstest!

- anonymous

@no-data see the pdf file.

- anonymous

ok

- anonymous

I think you need to apply the transformation to each vector of the basis.

- anonymous

and you form a matrix with the coefficients of the result in columns.

- anonymous

So would the first vector in the basis for f1 be [1,0,2] because of the standard basis [1,x,x^2]?

- anonymous

I thought that is the way, but I'm checking. if its true.

- anonymous

Hmm what is the result of apply the transformation to the f_1 vector?

- anonymous

I got 3 + 8t + 8 t^2

- alexwee123

ugh linear algebra o.0

- anonymous

haha true alex. It's sht sh(((ts

- anonymous

*the

- anonymous

\[T(f_1(t)) = f_1(2t+1)=1+2(2t+1)^2\]

- anonymous

I got \(3 + 8t + 8t^2\) am I right?

- anonymous

sec... I think there's something more you have to do. Let me pull up some pages from a book.

- anonymous

Ok

- anonymous

So it looks like you first have to plug 2t+1 into the x's in your standard P2 polynomial first.

- anonymous

So you'll have 4t^2+4t+1

- anonymous

what is your standard polynomial?

- anonymous

I guess I meant plug in 1 +2t^2 into our polynomial.
4(1+2t^2)^2 +4t +1 = 4(1+2t^2)(1+2t^2) +4t +1
=4(1 + 4t^2 +4t^4) +4t +1

- anonymous

P2: ax^2 +bx +c

- anonymous

See I'm really confused. I think I'm going to stop right there b/c I'm not on the right track I don't think.

- anonymous

You need to remember how to obtain the matrix of a transformation first.

- anonymous

Always go back to your definitions and well understood theorems brinethery.

- anonymous

Right now I don't remember well, and I don't have math books at work to help you as I wish. But I think that is the way.

- anonymous

take some rest if you need it.

- anonymous

are you allright?

- anonymous

I'm fine, I just really need help to this question

- anonymous

Ok.

- anonymous

How are you?

- anonymous

As I said you before, you just need to apply the transformation to each of the vectors of your basis. and form a matrix.

- anonymous

with the results aligned in columns.

- anonymous

http://www.youtube.com/watch?v=Du84AF2VOWA&feature=related

- anonymous

I mean: \[\left[\begin{matrix} F^T(f_1(t))& F^T(f_2(t)) & F^T(f_3(t)) &\end{matrix}\right]\]

- anonymous

Sorry I can't see you tube videos at work. =(

- anonymous

it's blocked.

- anonymous

That's okay

- anonymous

but what does it show the video?

- anonymous

Argentine tango

- anonymous

My goal in life is to travel to Buenos Aires and learn tango there

- anonymous

You mean one of the many goals on your life =P

- anonymous

I have no other goals. If I could just dance then I would be happy lol

- anonymous

look for punk tango on you tube.

- anonymous

that is the tango i want to dance haha

- anonymous

well thank you brinethery.

- anonymous

I really miss math.. snif snif haha

- anonymous

see you!

- anonymous

bye

Looking for something else?

Not the answer you are looking for? Search for more explanations.