anonymous
  • anonymous
Find the matrix of the linear transformation T(f(t)) = f(2t+1) from P2 to P2 with respect to the basis B (script B) = (f1 = 1 +2t^2, f2=1, f3=t)
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
halp!
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anonymous
  • anonymous
@No-data
anonymous
  • anonymous
no-dataaaa!

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anonymous
  • anonymous
It really doesn't
anonymous
  • anonymous
??
anonymous
  • anonymous
Fallingangel, don't ever take linear algebra. It is the worstest!
anonymous
  • anonymous
@no-data see the pdf file.
anonymous
  • anonymous
ok
anonymous
  • anonymous
I think you need to apply the transformation to each vector of the basis.
anonymous
  • anonymous
and you form a matrix with the coefficients of the result in columns.
anonymous
  • anonymous
So would the first vector in the basis for f1 be [1,0,2] because of the standard basis [1,x,x^2]?
anonymous
  • anonymous
I thought that is the way, but I'm checking. if its true.
anonymous
  • anonymous
Hmm what is the result of apply the transformation to the f_1 vector?
anonymous
  • anonymous
I got 3 + 8t + 8 t^2
alexwee123
  • alexwee123
ugh linear algebra o.0
anonymous
  • anonymous
haha true alex. It's sht sh(((ts
anonymous
  • anonymous
*the
anonymous
  • anonymous
\[T(f_1(t)) = f_1(2t+1)=1+2(2t+1)^2\]
anonymous
  • anonymous
I got \(3 + 8t + 8t^2\) am I right?
anonymous
  • anonymous
sec... I think there's something more you have to do. Let me pull up some pages from a book.
anonymous
  • anonymous
Ok
anonymous
  • anonymous
So it looks like you first have to plug 2t+1 into the x's in your standard P2 polynomial first.
anonymous
  • anonymous
So you'll have 4t^2+4t+1
anonymous
  • anonymous
what is your standard polynomial?
anonymous
  • anonymous
I guess I meant plug in 1 +2t^2 into our polynomial. 4(1+2t^2)^2 +4t +1 = 4(1+2t^2)(1+2t^2) +4t +1 =4(1 + 4t^2 +4t^4) +4t +1
anonymous
  • anonymous
P2: ax^2 +bx +c
anonymous
  • anonymous
See I'm really confused. I think I'm going to stop right there b/c I'm not on the right track I don't think.
anonymous
  • anonymous
You need to remember how to obtain the matrix of a transformation first.
anonymous
  • anonymous
Always go back to your definitions and well understood theorems brinethery.
anonymous
  • anonymous
Right now I don't remember well, and I don't have math books at work to help you as I wish. But I think that is the way.
anonymous
  • anonymous
take some rest if you need it.
anonymous
  • anonymous
are you allright?
anonymous
  • anonymous
I'm fine, I just really need help to this question
anonymous
  • anonymous
Ok.
anonymous
  • anonymous
How are you?
anonymous
  • anonymous
As I said you before, you just need to apply the transformation to each of the vectors of your basis. and form a matrix.
anonymous
  • anonymous
with the results aligned in columns.
anonymous
  • anonymous
http://www.youtube.com/watch?v=Du84AF2VOWA&feature=related
anonymous
  • anonymous
I mean: \[\left[\begin{matrix} F^T(f_1(t))& F^T(f_2(t)) & F^T(f_3(t)) &\end{matrix}\right]\]
anonymous
  • anonymous
Sorry I can't see you tube videos at work. =(
anonymous
  • anonymous
it's blocked.
anonymous
  • anonymous
That's okay
anonymous
  • anonymous
but what does it show the video?
anonymous
  • anonymous
Argentine tango
anonymous
  • anonymous
My goal in life is to travel to Buenos Aires and learn tango there
anonymous
  • anonymous
You mean one of the many goals on your life =P
anonymous
  • anonymous
I have no other goals. If I could just dance then I would be happy lol
anonymous
  • anonymous
look for punk tango on you tube.
anonymous
  • anonymous
that is the tango i want to dance haha
anonymous
  • anonymous
well thank you brinethery.
anonymous
  • anonymous
I really miss math.. snif snif haha
anonymous
  • anonymous
see you!
anonymous
  • anonymous
bye

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