## brinethery Group Title Find the matrix of the linear transformation T(f(t)) = f(2t+1) from P2 to P2 with respect to the basis B (script B) = (f1 = 1 +2t^2, f2=1, f3=t) 2 years ago 2 years ago

1. brinethery Group Title

halp!

2. brinethery Group Title

@No-data

3. brinethery Group Title

no-dataaaa!

4. No-data Group Title

It really doesn't

5. No-data Group Title

??

6. brinethery Group Title

Fallingangel, don't ever take linear algebra. It is the worstest!

7. brinethery Group Title

@no-data see the pdf file.

8. No-data Group Title

ok

9. No-data Group Title

I think you need to apply the transformation to each vector of the basis.

10. No-data Group Title

and you form a matrix with the coefficients of the result in columns.

11. brinethery Group Title

So would the first vector in the basis for f1 be [1,0,2] because of the standard basis [1,x,x^2]?

12. No-data Group Title

I thought that is the way, but I'm checking. if its true.

13. No-data Group Title

Hmm what is the result of apply the transformation to the f_1 vector?

14. No-data Group Title

I got 3 + 8t + 8 t^2

15. alexwee123 Group Title

ugh linear algebra o.0

16. brinethery Group Title

haha true alex. It's sht sh(((ts

17. brinethery Group Title

*the

18. No-data Group Title

$T(f_1(t)) = f_1(2t+1)=1+2(2t+1)^2$

19. No-data Group Title

I got $$3 + 8t + 8t^2$$ am I right?

20. brinethery Group Title

sec... I think there's something more you have to do. Let me pull up some pages from a book.

21. No-data Group Title

Ok

22. brinethery Group Title

So it looks like you first have to plug 2t+1 into the x's in your standard P2 polynomial first.

23. brinethery Group Title

So you'll have 4t^2+4t+1

24. No-data Group Title

25. brinethery Group Title

I guess I meant plug in 1 +2t^2 into our polynomial. 4(1+2t^2)^2 +4t +1 = 4(1+2t^2)(1+2t^2) +4t +1 =4(1 + 4t^2 +4t^4) +4t +1

26. brinethery Group Title

P2: ax^2 +bx +c

27. brinethery Group Title

See I'm really confused. I think I'm going to stop right there b/c I'm not on the right track I don't think.

28. No-data Group Title

You need to remember how to obtain the matrix of a transformation first.

29. No-data Group Title

Always go back to your definitions and well understood theorems brinethery.

30. No-data Group Title

Right now I don't remember well, and I don't have math books at work to help you as I wish. But I think that is the way.

31. No-data Group Title

take some rest if you need it.

32. No-data Group Title

are you allright?

33. brinethery Group Title

I'm fine, I just really need help to this question

34. No-data Group Title

Ok.

35. brinethery Group Title

How are you?

36. No-data Group Title

As I said you before, you just need to apply the transformation to each of the vectors of your basis. and form a matrix.

37. No-data Group Title

with the results aligned in columns.

38. brinethery Group Title
39. No-data Group Title

I mean: $\left[\begin{matrix} F^T(f_1(t))& F^T(f_2(t)) & F^T(f_3(t)) &\end{matrix}\right]$

40. No-data Group Title

Sorry I can't see you tube videos at work. =(

41. No-data Group Title

it's blocked.

42. brinethery Group Title

That's okay

43. No-data Group Title

but what does it show the video?

44. brinethery Group Title

Argentine tango

45. brinethery Group Title

My goal in life is to travel to Buenos Aires and learn tango there

46. No-data Group Title

You mean one of the many goals on your life =P

47. brinethery Group Title

I have no other goals. If I could just dance then I would be happy lol

48. No-data Group Title

look for punk tango on you tube.

49. No-data Group Title

that is the tango i want to dance haha

50. No-data Group Title

well thank you brinethery.

51. No-data Group Title

I really miss math.. snif snif haha

52. No-data Group Title

see you!

53. brinethery Group Title

bye