A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
can someone please help get the answer
Solve 2^(x + 3) = 7
Answer
a.x ≈ –5.19
b.x ≈ 2.81
c.x ≈ –0.19
d.x ≈ 0.9
anonymous
 4 years ago
can someone please help get the answer Solve 2^(x + 3) = 7 Answer a.x ≈ –5.19 b.x ≈ 2.81 c.x ≈ –0.19 d.x ≈ 0.9

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You can simplify it better by: 2^x + 2^3 = 7 Or go to http://www.wolframalpha.com/input/?i=solve+2^%28x%2B3%29%3D7 The answer is C.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I havent done "log" in a looooong time, so sorry i cant help with that part

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@sam that should be "2^x *2^3" and not '+'.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[2^{x} \times 2^{3} = 7 \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I GOT IT!! Ok, so: \[2^{x} \times 8 =7\] \[2^{x}= 7/8\] \[x=\log(7/8) \div \log(2) ; x=0.19\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.