Here's the question you clicked on:
greeneyes<3
What is the domain & range of y=2 sqrt. x ?
domain and range is same as the square root function this function is only vertically stretched by a factor of two so therefore the domain and range is not affected :)
:( my answer was D: all real #s R: all real #s But I think that is wrong...
ya it is because x cannot be negative, you can't square root a negative unless you want imaginary :/
so because the values of x cannot be negative then the y values cannot be negative either so that leaves you with a domain of [0,infinity) and a range of [0,infinity)
|dw:1337382785574:dw|
D: x >\= 0 r: y >\= 0 ? I'm still confused. :/
well i told you that the values of x cannot be negative because you cannot square root a negatives so all values of x must be greater than or equal to zero and because y is the output of the x values y must also be greater than or equal to 0
Kay thanks :) I'm sorry but I'm just so awful at math...