A community for students.
Here's the question you clicked on:
 0 viewing
greeneyes<3
 2 years ago
What is the domain & range of
y=2 sqrt. x ?
greeneyes<3
 2 years ago
What is the domain & range of y=2 sqrt. x ?

This Question is Closed

alexwee123
 2 years ago
Best ResponseYou've already chosen the best response.1domain and range is same as the square root function this function is only vertically stretched by a factor of two so therefore the domain and range is not affected :)

greeneyes<3
 2 years ago
Best ResponseYou've already chosen the best response.0:( my answer was D: all real #s R: all real #s But I think that is wrong...

alexwee123
 2 years ago
Best ResponseYou've already chosen the best response.1ya it is because x cannot be negative, you can't square root a negative unless you want imaginary :/

alexwee123
 2 years ago
Best ResponseYou've already chosen the best response.1so because the values of x cannot be negative then the y values cannot be negative either so that leaves you with a domain of [0,infinity) and a range of [0,infinity)

alexwee123
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1337382785574:dw

greeneyes<3
 2 years ago
Best ResponseYou've already chosen the best response.0D: x >\= 0 r: y >\= 0 ? I'm still confused. :/

alexwee123
 2 years ago
Best ResponseYou've already chosen the best response.1well i told you that the values of x cannot be negative because you cannot square root a negatives so all values of x must be greater than or equal to zero and because y is the output of the x values y must also be greater than or equal to 0

greeneyes<3
 2 years ago
Best ResponseYou've already chosen the best response.0Kay thanks :) I'm sorry but I'm just so awful at math...
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.