What is the domain & range of y=2 sqrt. x ?

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What is the domain & range of y=2 sqrt. x ?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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domain and range is same as the square root function this function is only vertically stretched by a factor of two so therefore the domain and range is not affected :)
:( my answer was D: all real #s R: all real #s But I think that is wrong...
ya it is because x cannot be negative, you can't square root a negative unless you want imaginary :/

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so because the values of x cannot be negative then the y values cannot be negative either so that leaves you with a domain of [0,infinity) and a range of [0,infinity)
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D: x >\= 0 r: y >\= 0 ? I'm still confused. :/
well i told you that the values of x cannot be negative because you cannot square root a negatives so all values of x must be greater than or equal to zero and because y is the output of the x values y must also be greater than or equal to 0
Kay thanks :) I'm sorry but I'm just so awful at math...
np:)

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