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greeneyes<3

  • 3 years ago

What is the domain & range of y=2 sqrt. x ?

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  1. alexwee123
    • 3 years ago
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    domain and range is same as the square root function this function is only vertically stretched by a factor of two so therefore the domain and range is not affected :)

  2. greeneyes<3
    • 3 years ago
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    :( my answer was D: all real #s R: all real #s But I think that is wrong...

  3. alexwee123
    • 3 years ago
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    ya it is because x cannot be negative, you can't square root a negative unless you want imaginary :/

  4. alexwee123
    • 3 years ago
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    so because the values of x cannot be negative then the y values cannot be negative either so that leaves you with a domain of [0,infinity) and a range of [0,infinity)

  5. alexwee123
    • 3 years ago
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    |dw:1337382785574:dw|

  6. greeneyes<3
    • 3 years ago
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    D: x >\= 0 r: y >\= 0 ? I'm still confused. :/

  7. alexwee123
    • 3 years ago
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    well i told you that the values of x cannot be negative because you cannot square root a negatives so all values of x must be greater than or equal to zero and because y is the output of the x values y must also be greater than or equal to 0

  8. greeneyes<3
    • 3 years ago
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    Kay thanks :) I'm sorry but I'm just so awful at math...

  9. alexwee123
    • 3 years ago
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    np:)

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