A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
Silenthill
 2 years ago
integrate (x+1)/(x1)
Silenthill
 2 years ago
integrate (x+1)/(x1)

This Question is Closed

mahmit2012
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1337384917720:dw

lolampig
 2 years ago
Best ResponseYou've already chosen the best response.6\[{x+1 \over x1} = {(x1) + 2 \over x1} = 1 + {2 \over x1}\] Now we let u = x1, so that du/dx = 1, and du = dx. Then \[\int\limits 1 + {2 \over x1} dx = \int\limits 1 + {2 \over u} du\]The integral of 1/u is lnu, and the integral of 1 is u, so we have the integral to be \[u + 2\lnu + c = (x1) + 2\lnx1 + c =x + 2\lnx1 + c\]Where the 1 was absorbed into the constant of integration in the last step.

Silenthill
 2 years ago
Best ResponseYou've already chosen the best response.0very helpful thank you
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.