kelseak
i need helpppp
3x+9
9



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UnkleRhaukus
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division?

kelseak
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yes

ParthKohli
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\(\Large \color{MidnightBlue}{\Rightarrow {3(x  3) \over 3(3)} }\)
\(\Large \color{MidnightBlue}{\Rightarrow {x  3 \over 3} }\)
\(\Large \color{MidnightBlue}{\Rightarrow {x + 3 \over 3} }\)

ParthKohli
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Got it now?

UnkleRhaukus
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\[\frac{3x+9}{9}\]\[=\frac{3(x+3)}{3(3)}\]\[=\frac{x+3}{3}\]\[=\frac{x}{3}+\frac33\]\[=1\frac x3\]

ParthKohli
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First, I factored both the numerators and denominators, then I cancelled them out.

nilankshi
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thats' rite parth i was also doing the same..but u done it first..

ParthKohli
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Hahaha :D

kelseak
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i kinda get it, thanks (:

ParthKohli
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Haha no probs :D

nilankshi
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keep it up parh..;)

ParthKohli
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Thanks @nilankshi

nilankshi
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yr welcome parth