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kelseak

  • 2 years ago

i need helpppp -3x+9 9

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  1. UnkleRhaukus
    • 2 years ago
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    division?

  2. kelseak
    • 2 years ago
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    yes

  3. ParthKohli
    • 2 years ago
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    \(\Large \color{MidnightBlue}{\Rightarrow {-3(x - 3) \over -3(-3)} }\) \(\Large \color{MidnightBlue}{\Rightarrow {x - 3 \over -3} }\) \(\Large \color{MidnightBlue}{\Rightarrow {-x + 3 \over 3} }\)

  4. ParthKohli
    • 2 years ago
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    Got it now?

  5. UnkleRhaukus
    • 2 years ago
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    \[\frac{-3x+9}{9}\]\[=\frac{3(-x+3)}{3(3)}\]\[=\frac{-x+3}{3}\]\[=\frac{-x}{3}+\frac33\]\[=1-\frac x3\]

  6. ParthKohli
    • 2 years ago
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    First, I factored both the numerators and denominators, then I cancelled them out.

  7. nilankshi
    • 2 years ago
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    thats' rite parth i was also doing the same..but u done it first..

  8. ParthKohli
    • 2 years ago
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    Hahaha :D

  9. kelseak
    • 2 years ago
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    i kinda get it, thanks (:

  10. ParthKohli
    • 2 years ago
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    Haha no probs :D

  11. nilankshi
    • 2 years ago
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    keep it up parh..;)

  12. ParthKohli
    • 2 years ago
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    Thanks @nilankshi

  13. nilankshi
    • 2 years ago
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    yr welcome parth

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