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i need helpppp -3x+9 9

Mathematics
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division?
yes
\(\Large \color{MidnightBlue}{\Rightarrow {-3(x - 3) \over -3(-3)} }\) \(\Large \color{MidnightBlue}{\Rightarrow {x - 3 \over -3} }\) \(\Large \color{MidnightBlue}{\Rightarrow {-x + 3 \over 3} }\)

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\[\frac{-3x+9}{9}\]\[=\frac{3(-x+3)}{3(3)}\]\[=\frac{-x+3}{3}\]\[=\frac{-x}{3}+\frac33\]\[=1-\frac x3\]
First, I factored both the numerators and denominators, then I cancelled them out.
thats' rite parth i was also doing the same..but u done it first..
Hahaha :D
i kinda get it, thanks (:
Haha no probs :D
keep it up parh..;)
Thanks @nilankshi
yr welcome parth

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