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ajprincess

plzz check.

  • one year ago
  • one year ago

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  1. ajprincess
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    #include<iostream> using namespace std; class Operation { private: int answer; int numberA; int numberB; public: int addition(int numberA,int numberB); int subtraction(int numberA,int numberB); int multiplication(int numberA,int numberB); int division(int numberA,int numberB); int getNumberA(); void setNumberA(int numberA); int getNumberB(); void setNumberB(int result); void printOnScreen(int answer); }; int Operation::getNumberA() { return numberA; } void Operation::setNumberA(int A) { numberA=A; } int Operation::getNumberB() { return numberB; } void Operation::setNumberB(int B) { numberB=B; } int Operation::addition(int numberA,int numberB) { return (numberA+numberB); } int Operation::subtraction(int numberA,int numberB) { return (numberA-numberB); } int Operation::multiplication(int numberA,int numberB) { return (numberA*numberB); } int Operation::division(int numberA,int numberB) { return (numberA/numberB); } void Operation::printOnScreen(int answer) { cout<<answer<<endl; } int main() { Operation o; int numberA, numberB, answer, choice; o.setNumberA(8); o.setNumberB(7); cout<<"Enter the choice:"; cin>>choice; switch(choice) { case 1: o.addition(numberA,numberB); break; case 2: o.subtraction(numberA,numberB); break; case 3: o.multiplication(numberA,numberB); break; case 4: o.division(numberA,numberB); break; default: cout<<"Wrong choice"<<endl; } o.printOnScreen(int answer); system("PAUSE"); return 0; }

    • one year ago
  2. agdgdgdgwngo
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    about your printOnScreen method: Shouldn't it take no arguments, and just print out the private memver `answer'? otherwise the last statement in main before system(pause) (o.printOnScreen(int answer);) is a syntax error :)

    • one year ago
  3. agdgdgdgwngo
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    private member* `answer' something like void Operation::printOnScreen() { cout << answer << endl; }

    • one year ago
  4. ajprincess
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    This is the question Write a C++ program with multiple methods to intake the two integers and do the, Addition, Subtraction, Multiplication, and Division. Hints: 1.Use the following class diagram for your implementation. 2.On your main method u hav to implement selection and repetition of the arithmetic operation 3.You can include any more methods if required.

    • one year ago
  5. agdgdgdgwngo
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    ah I get it now. you need to either declare an answer variable to store the results of adding/multiplying/etc and supply it as an arugment to void Operation::printOnScreen(int answer), or you need to change the adding/subtracting/etc methods to change the `answer' member variable

    • one year ago
  6. ajprincess
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    Class diagram Arithmetic int numberA int numberB int answer int addition int subtraction int multiplication int division void getAnswer void setAnswer void printOnScreen

    • one year ago
  7. agdgdgdgwngo
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    with that diagram, it looks like you are just missing the getAnswer and setAnswer methods.

    • one year ago
  8. ajprincess
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    yep. bt am trying to include it. am totally confused.

    • one year ago
  9. agdgdgdgwngo
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    something like: int Operation::getAnswer() { return answer } void Operation::setAnswer(int answer) { this->answer = answer; }

    • one year ago
  10. ajprincess
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    ya I knw that. bt it is given in the class diagram as void getAnswer.

    • one year ago
  11. agdgdgdgwngo
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    that's confusing then; getter methods are supposed to return something, no? :(

    • one year ago
  12. ajprincess
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    ya u r right. and also i dnt knw vt to include in printOnScreen() .:(

    • one year ago
  13. agdgdgdgwngo
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    from your first post, your printOnScreen looks fine. when you use it in main you can do something like: o.printOnScreen(o.getAnswer());

    • one year ago
  14. ajprincess
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    #include<iostream> using namespace std; class Arithmetic { private: int answer; int numberA; int numberB; public: int addition(int numberA,int numberB); int subtraction(int numberA,int numberB); int multiplication(int numberA,int numberB); int division(int numberA,int numberB); int getNumberA(); void setNumberA(int numberA); int getNumberB(); void setNumberB(int result); int getAnswer(); void setAnswer(int result); void printOnScreen(); }; int Arithmetic::getNumberA() { return numberA; } void Arithmetic::setNumberA(int A) { numberA=A; } int Arithmetic::getNumberB() { return numberB; } void Arithmetic::setNumberB(int B) { numberB=B; } int Arithmetic::addition(int numberA,int numberB) { return (numberA+numberB); } int Arithmetic::subtraction(int numberA,int numberB) { return (numberA-numberB); } int Arithmetic::multiplication(int numberA,int numberB) { return (numberA*numberB); } int Arithmetic::division(int numberA,int numberB) { return (numberA/numberB); } int Arithmetic::getAnswer() { return answer; } void Arithmetic::setAnswer(int result) { answer=result; } void Arithmetic::printOnScreen() { cout<<answer<<endl; } int main() { Arithmetic a; int numberA, numberB, answer, choice; a.setNumberA(8); a.setNumberB(7); cout<<"Enter the choice:"; cin>>choice; switch(choice) { case 1: a.addition(numberA,numberB); break; case 2: a.subtraction(numberA,numberB); break; case 3: a.multiplication(numberA,numberB); break; case 4: a.division(numberA,numberB); break; default: cout<<"Wrong choice"<<endl; } a.printOnScreen(); system("PAUSE"); return 0; }

    • one year ago
  15. ajprincess
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    Bt I dnt get the expected output. Dnt knw y.:(

    • one year ago
  16. shivam_bhalla
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    What is the output you expect?

    • one year ago
  17. ajprincess
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    as u can see I hav passed the values 8 and 7 for A and B. If my choice is 1 I should get 15 as the output. Bt I dnt get t.

    • one year ago
  18. shivam_bhalla
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    @ajprincess , int Arithmetic::addition(int numberA,int numberB) This is wrong. a.addition(numberA,numberB); It should be int temp; temp =a.addition(numberA,numberB);

    • one year ago
  19. shivam_bhalla
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    Do you understand that you were not storing the value returnnd by " int Arithmetic::addition(int numberA,int numberB) " in a variable

    • one year ago
  20. ajprincess
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    I hav already declared answer in my main method. Nw I wrote this answer=a.addition(numberA,numberB) It's correct nw. Isnt t?

    • one year ago
  21. shivam_bhalla
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    Nope @ajprincess , it should be a.answer=a.addition(numberA,numberB); answer is private member function of Arithmetic

    • one year ago
  22. shivam_bhalla
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    BUt why did you declare another answer varible in main () ??

    • one year ago
  23. ajprincess
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    If I change it like this I get an error saying that answer is private.

    • one year ago
  24. shivam_bhalla
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    Got it. It should be answer=a.addition(numberA,numberB); setAnswer(answer); Now it should be fine

    • one year ago
  25. ajprincess
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    bt it reports an error as answer undeclared

    • one year ago
  26. shivam_bhalla
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    Sorry @ Ajprincess. It should be answer=a.addition(numberA,numberB); a.setAnswer(answer);

    • one year ago
  27. ajprincess
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    bt I wrote it as a.setAnswer(answer)

    • one year ago
  28. shivam_bhalla
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    LOl @ajprincess . I just noticed another mistake. int temp, temp1; temp=getNumberA(); temp1=getNumberB(); answer=a.addition(temp,temp1); a.setAnswer(answer);

    • one year ago
  29. ajprincess
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    if I make this many mistakes dnt knw hw I am gonna finish this within 45mints. Thanxxxxxxx a lot. @Shivam_bhalla. U r so helpful.

    • one year ago
  30. shivam_bhalla
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    LOL. No problem. I also learnt by making these mistakes :P

    • one year ago
  31. ajprincess
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    U too @agdgdgdgwngo are really helpful. Thanxxxxx a lot.

    • one year ago
  32. ajprincess
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    in my question repetition of arithmetic operation is askd to b implemented. Hw wud i do that?@Shivam_bhalla

    • one year ago
  33. ajprincess
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    @shivam_bhalla

    • one year ago
  34. shivam_bhalla
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    I was busy at another question. If your question is asking for repeting of arithmetic operation then you can add the (Number 1 +Number 2)+number 1

    • one year ago
  35. ajprincess
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    can u please show with my function declarations?

    • one year ago
  36. shivam_bhalla
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    @ajprincess , why don't you try by yourself?. Learn by trying on your own. You will get the logic. Then try to implement that logic :D

    • one year ago
  37. ajprincess
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    k thanxxxx a lot. @shivam_bhalla

    • one year ago
  38. shivam_bhalla
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    np ;). Remember. Computer is a easy subject. Just practice it on your own by making your own programs :)

    • one year ago
  39. ajprincess
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    Sure.:)

    • one year ago
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