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Can someone please explain why the cycloid curve has a vertical movement on the cusps? Thank you!
 one year ago
 one year ago
Can someone please explain why the cycloid curve has a vertical movement on the cusps? Thank you!
 one year ago
 one year ago

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As far as I understand it. . . the instantaneous direction of motion is vertical because the tangent to the graph of the motion at the cusp is vertical. Direction: The vertical tangent is explained in both the lecture (using approximations) and the Related Reading (using calculus). The slope (dy/dx) of the tangent to the curve signifies the direction of the curve, which in this case is the direction of motion. So the instantaneous direction of motion is vertical. Velocity: However, the Related Reading explains that the velocity of the point at the cusp is 0. So, the point has no instantaneous movement at the cusp (v=change in position/change in time=0). (We have position\[OP=<x,y>=<a \thetaasin \theta, aacos \theta>\]. So \[velocity =d(OP)/d \theta=<aacos \theta,asin \theta>\] which at the cusp is\[<aacos0, asin0>=<0,0>.)\] So at the cusp, the direction of motion is vertical, while the instantaneous velocity is 0.
 one year ago
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