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QRAwarrior
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Suppose you have, in the denominator of your integral, the expression of the form x^2  a^2. You want to use trigonometric substitution with this. How would the resulting triangle look like?
ATTEMPT:
 2 years ago
 2 years ago
QRAwarrior Group Title
Suppose you have, in the denominator of your integral, the expression of the form x^2  a^2. You want to use trigonometric substitution with this. How would the resulting triangle look like? ATTEMPT:
 2 years ago
 2 years ago

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QRAwarrior Group TitleBest ResponseYou've already chosen the best response.1
dw:1337434470844:dw
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.0
I'm sure I follow you, but some of the rules for trig substitution in integrals are described here: http://en.wikipedia.org/wiki/Trigonometric_substitution maybe that will help you.
 2 years ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.0
*I'm NOT sure...
 2 years ago

QRAwarrior Group TitleBest ResponseYou've already chosen the best response.1
Got any ideas @shivam_bhalla?
 2 years ago

shivam_bhalla Group TitleBest ResponseYou've already chosen the best response.1
Your trigonometric substitution for such a case will be \[x= asec (\theta)\] So \[\sec(\theta)=x/a\] dw:1337436343334:dw
 2 years ago

shivam_bhalla Group TitleBest ResponseYou've already chosen the best response.1
yes @QRAwarrior , you have done it correctly :)
 2 years ago

QRAwarrior Group TitleBest ResponseYou've already chosen the best response.1
Because I thought that there would be a side with "x^2  a^2"
 2 years ago

QRAwarrior Group TitleBest ResponseYou've already chosen the best response.1
Anyways, thanks a lot.
 2 years ago

shivam_bhalla Group TitleBest ResponseYou've already chosen the best response.1
yw :)
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.2
okay, think about this > if I have something like \[\frac{1}{x^2  a^2}\] I would be very happy, if I can reduce (x^2  a^2) to a monomial. Right? Because that become very easy to integrate after I convert it into a form in the numerator. Now, if I remember the basics: \[tan^2m +1 = sec^2m\] and \[sin^2m + cos^2m = 1\] Now, I see, if I can get some think like a^2 *(sec^2(m) instead of the x^2, I can manage to get a a^2 tan^x in the denominator, and some ".....dm" in the numerator, which would be pretty easy to integrate then. So, I use the substitution: x=asecm and proceed. I get: dx= a secm tanm dm i plug this in the numerator in the place of dx. and then evaluate the integral pretty easily.
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.2
I just have to think of some ways to remove the radical sign if present, or make the denominator simpler.
 2 years ago
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