A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Suppose you have, in the denominator of your integral, the expression of the form x^2  a^2. You want to use trigonometric substitution with this. How would the resulting triangle look like?
ATTEMPT:
anonymous
 4 years ago
Suppose you have, in the denominator of your integral, the expression of the form x^2  a^2. You want to use trigonometric substitution with this. How would the resulting triangle look like? ATTEMPT:

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1337434470844:dw

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0I'm sure I follow you, but some of the rules for trig substitution in integrals are described here: http://en.wikipedia.org/wiki/Trigonometric_substitution maybe that will help you.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Got any ideas @shivam_bhalla?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Your trigonometric substitution for such a case will be \[x= asec (\theta)\] So \[\sec(\theta)=x/a\] dw:1337436343334:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes @QRAwarrior , you have done it correctly :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Because I thought that there would be a side with "x^2  a^2"

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Anyways, thanks a lot.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay, think about this > if I have something like \[\frac{1}{x^2  a^2}\] I would be very happy, if I can reduce (x^2  a^2) to a monomial. Right? Because that become very easy to integrate after I convert it into a form in the numerator. Now, if I remember the basics: \[tan^2m +1 = sec^2m\] and \[sin^2m + cos^2m = 1\] Now, I see, if I can get some think like a^2 *(sec^2(m) instead of the x^2, I can manage to get a a^2 tan^x in the denominator, and some ".....dm" in the numerator, which would be pretty easy to integrate then. So, I use the substitution: x=asecm and proceed. I get: dx= a secm tanm dm i plug this in the numerator in the place of dx. and then evaluate the integral pretty easily.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I just have to think of some ways to remove the radical sign if present, or make the denominator simpler.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.