## Sup_open~study 3 years ago i need some help :)

1. Sup_open~study

2. Sup_open~study

do i do cos ??

3. maheshmeghwal9

no, u should know that cosecx=h/p

4. maheshmeghwal9

u know 'h' but 'p' is opposite to the angle considered which is 'M'.

5. maheshmeghwal9

We find PN by Pythagoras theorem & get the answer by putting the values; i.e. cosecM=h/p=PM/PN=17/15.

6. Sup_open~study

can you draw it plz thank you so much :)

7. maheshmeghwal9

yw:) but what do u wanna make draw through me?

8. maheshmeghwal9

hello!

9. Sup_open~study

i was just wondering if you can draw the triangle and work it out :)

10. maheshmeghwal9

k! but u don't have any doubts now or have u?

11. Sup_open~study

i have doubts :(

12. maheshmeghwal9

wait a minute:)

13. Sup_open~study

k :)

14. maheshmeghwal9

|dw:1337451865093:dw| Here , try pythagorus theroem; since angle PNM is given 90 degree in the figure thus we get

15. maheshmeghwal9

$x^2+8^2=17^2$

16. maheshmeghwal9

$x=\sqrt{17^2-8^2}$

17. maheshmeghwal9

$x=\sqrt{289-64}$

18. maheshmeghwal9

$x=\sqrt{225}=15=PN:)$

19. maheshmeghwal9

& we have formula cosec x= hypotenuse/perpendicular=1/sin x=h/p=PM/PN=17/15.

20. Sup_open~study

ah thanks man i got it now :) your awesome

21. maheshmeghwal9

Now what doubt do u have?

22. Sup_open~study

none :)

23. maheshmeghwal9

yw:)

24. Sup_open~study

have a good day :)

25. maheshmeghwal9

same to u:) but here is night!