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Sup_open~study

  • 2 years ago

i need some help :)

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  1. Sup_open~study
    • 2 years ago
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  2. Sup_open~study
    • 2 years ago
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    do i do cos ??

  3. maheshmeghwal9
    • 2 years ago
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    no, u should know that cosecx=h/p

  4. maheshmeghwal9
    • 2 years ago
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    u know 'h' but 'p' is opposite to the angle considered which is 'M'.

  5. maheshmeghwal9
    • 2 years ago
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    We find PN by Pythagoras theorem & get the answer by putting the values; i.e. cosecM=h/p=PM/PN=17/15.

  6. Sup_open~study
    • 2 years ago
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    can you draw it plz thank you so much :)

  7. maheshmeghwal9
    • 2 years ago
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    yw:) but what do u wanna make draw through me?

  8. maheshmeghwal9
    • 2 years ago
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    hello!

  9. Sup_open~study
    • 2 years ago
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    i was just wondering if you can draw the triangle and work it out :)

  10. maheshmeghwal9
    • 2 years ago
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    k! but u don't have any doubts now or have u?

  11. Sup_open~study
    • 2 years ago
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    i have doubts :(

  12. maheshmeghwal9
    • 2 years ago
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    wait a minute:)

  13. Sup_open~study
    • 2 years ago
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    k :)

  14. maheshmeghwal9
    • 2 years ago
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    |dw:1337451865093:dw| Here , try pythagorus theroem; since angle PNM is given 90 degree in the figure thus we get

  15. maheshmeghwal9
    • 2 years ago
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    \[x^2+8^2=17^2\]

  16. maheshmeghwal9
    • 2 years ago
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    \[x=\sqrt{17^2-8^2}\]

  17. maheshmeghwal9
    • 2 years ago
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    \[x=\sqrt{289-64}\]

  18. maheshmeghwal9
    • 2 years ago
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    \[x=\sqrt{225}=15=PN:)\]

  19. maheshmeghwal9
    • 2 years ago
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    & we have formula cosec x= hypotenuse/perpendicular=1/sin x=h/p=PM/PN=17/15.

  20. Sup_open~study
    • 2 years ago
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    ah thanks man i got it now :) your awesome

  21. maheshmeghwal9
    • 2 years ago
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    Now what doubt do u have?

  22. Sup_open~study
    • 2 years ago
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    none :)

  23. maheshmeghwal9
    • 2 years ago
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    yw:)

  24. Sup_open~study
    • 2 years ago
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    have a good day :)

  25. maheshmeghwal9
    • 2 years ago
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    same to u:) but here is night!

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