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Stephanizer

  • 3 years ago

Identify the 12th term of a geometric sequence where a1 = 8 and a6 = –8,192.

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  1. guykubpom
    • 3 years ago
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    a6 = a1*r^5 -8192 = 8*r^5 r^5 = -1024 r = -2 so a12 = a1*r^11 = 8*(-2)^11 = -16384 i guess

  2. Stephanizer
    • 3 years ago
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    ahhhh, that not in my choice of answerss:(

  3. guykubpom
    • 3 years ago
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    ahh I see now I got dizzy again lol it's too late here r = -4

  4. guykubpom
    • 3 years ago
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    so a12 = 8*(-4)^11 sorry for many mistakes lol

  5. Stephanizer
    • 3 years ago
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    ahh, thats not good!:(

  6. Stephanizer
    • 3 years ago
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    but be sorry you have no idea how helpful you are(:

  7. Stephanizer
    • 3 years ago
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    yess thats right!

  8. Stephanizer
    • 3 years ago
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    what about Identify the 17th term of a geometric sequence where a1 = 16 and a5 = 150.06. Round the common ratio and 17th term to the nearest hundredth.

  9. guykubpom
    • 3 years ago
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    a5 = a1*r^4 150.6 = 16*r^4 so u can figure r by using calculator 17th term to the nearest hundredth?? I don't understand my eng is not good enough lol

  10. Stephanizer
    • 3 years ago
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    haha ummm dont worry about that part? so like Identify the 17th term of a geometric sequence where a1 = 16 and a5 = 150.06. Round the common ratio and 17th term

  11. campbell_st
    • 3 years ago
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    stephanizer you need to evaluate the answer for your 1st term \[T _{12} = 8\times(-4)^{11}\] as the maths is correct.

  12. guykubpom
    • 3 years ago
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    ok r^4 is approximately 6.4 so a17 = a1*r^16 = a1*((r^4))^4 = 8*(6.4)^4=.....

  13. guykubpom
    • 3 years ago
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    but I want to understand eng too lol

  14. guykubpom
    • 3 years ago
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    no no r is approximately 9.4 lol

  15. campbell_st
    • 3 years ago
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    I got \[150.6 = 16r^4\] r = 1.75 then \[T _{17} = 16 \times(1.75)^{16} =123802\]

  16. guykubpom
    • 3 years ago
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    ^^ how you figure r out ?? did you use calculator??

  17. campbell_st
    • 3 years ago
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    \[r^4 = \frac{150.6}{16}\] then \[r = \sqrt[4]{9.4125} = 1.7499\]

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