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Stephanizer
Identify the 12th term of a geometric sequence where a1 = 8 and a6 = –8,192.
a6 = a1*r^5 -8192 = 8*r^5 r^5 = -1024 r = -2 so a12 = a1*r^11 = 8*(-2)^11 = -16384 i guess
ahhhh, that not in my choice of answerss:(
ahh I see now I got dizzy again lol it's too late here r = -4
so a12 = 8*(-4)^11 sorry for many mistakes lol
ahh, thats not good!:(
but be sorry you have no idea how helpful you are(:
what about Identify the 17th term of a geometric sequence where a1 = 16 and a5 = 150.06. Round the common ratio and 17th term to the nearest hundredth.
a5 = a1*r^4 150.6 = 16*r^4 so u can figure r by using calculator 17th term to the nearest hundredth?? I don't understand my eng is not good enough lol
haha ummm dont worry about that part? so like Identify the 17th term of a geometric sequence where a1 = 16 and a5 = 150.06. Round the common ratio and 17th term
stephanizer you need to evaluate the answer for your 1st term \[T _{12} = 8\times(-4)^{11}\] as the maths is correct.
ok r^4 is approximately 6.4 so a17 = a1*r^16 = a1*((r^4))^4 = 8*(6.4)^4=.....
but I want to understand eng too lol
no no r is approximately 9.4 lol
I got \[150.6 = 16r^4\] r = 1.75 then \[T _{17} = 16 \times(1.75)^{16} =123802\]
^^ how you figure r out ?? did you use calculator??
\[r^4 = \frac{150.6}{16}\] then \[r = \sqrt[4]{9.4125} = 1.7499\]