one integer is 8 less than 4 times another integer. the product of the two integers is 60. What are the two integers? show work

- anonymous

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

- katieb

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- slaaibak

Call the one integer x.
call the other one y
x = 4y - 8
xy = 60
Solve this.

- anonymous

can you help solve it?

- slaaibak

Substitute the x=4y-8 into the second equation

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- slaaibak

you will get (4y -8)y = 60
solve for y.
then solve for x

- anonymous

Here's the process, my little sugarplum:
Pick your favorite equation and your favorite variable in that equation. Solve for that variable.
Now, use that to substitute into the OTHER equation. This will give you an equation with just one variable in it =)
Solve for that variable, and you should just get a number.
Now, you know one variable, so you can look back at either of the first equations and use that variable to solve for the other one.

- anonymous

i got y=-15 and x=-68?

- anonymous

im not positive that thats correct

- anonymous

no =( I don't think so.

- slaaibak

Try again.

- anonymous

i dont know what i did wrong :/

- anonymous

Show me your work, okay?

- anonymous

ok 60=(4y-8)y
60=4y-8y
60/-4 = -4y/-4
y=-15

- slaaibak

The problem lies in line 2

- anonymous

x= 4(-15)-8
x= -60-8
x=-68

- anonymous

what the problem? :o

- anonymous

(4y-8)y = 4y^2 -8y

- anonymous

distribute, sweet thang.

- anonymous

whoops! forgot the to square it. but then there are no like terms to combine how would we solve
60= 4y^2-8y

- anonymous

Well, that's a whole 'nother kind of problem, and I'm guessing you've actually had a lot of practice with it, but it can be tricky, I understand.
The most common ways are factoring or quadratic formula.
Sound familiar?

- anonymous

yes we have to move the 60 over so it becomes a zero so then we have the values a b c for quadratic equation

- anonymous

Good =)
And actually, if you want to try factoring, it works nicely for this one. But I'm a fan of the quad formula, since it always works.

- anonymous

Yes =) Take out a common factor of 4 first though.

- anonymous

2 and 2

- anonymous

It makes it a lot easier.

- anonymous

Nooo
show me your factoring, please.

- anonymous

4? isnt is 2 and 2 or 4 and 1?

- anonymous

noope. show me your factoring.

- anonymous

from 4y^2 -8y-60 = 0

- anonymous

4y*y ?

- anonymous

...
okay you aren't good at factoring. That's okay. A lot of people aren't. Use the quadratic formula.

- anonymous

ok

- anonymous

I only say that because it's a whole different issue. We can work on it another time =)

- anonymous

ok after i do the quadratic equation i will get 2 different answers and those will be the answer to the problem right?

- anonymous

Re-read the problem and tell me if we have answered the question yet.

- anonymous

i did but i don't know won't that only find x and not y?

- anonymous

Right. Well actually, it finds y. Right?

- anonymous

i think so?

- anonymous

We wrote our two equations. We substituted into one of them and got an equation with just one variable, y. We're now using the quadratic formula to solve for that variable.
It's a little bit confusing because we're getting two possibilities for that variable, but we're still only solving for the one variable. We don't know the second variable yet.

- anonymous

yes it seems so confusing
i got fractions for both answers
-1/12 and 1/20
is that correct?

- anonymous

=/ I don't know what mistake you made.

- anonymous

i dont know either :(

- anonymous

\[\frac{-b \pm \sqrt{b^2 - 4ac}}{2a} = \frac{-(-8) \pm \sqrt{(-8)^2-4(4)(-60)}}{2(4)}\]

- anonymous

You probably just messed up on a sign somewhere. Did you plug in like that?

- anonymous

oh i see what i did im sorry i was doing 2ac instead of 2a

- anonymous

Ah =)

- anonymous

x= 5 and x= -3?

- anonymous

Good. Except we were solving for y. It's important because of the next step.

- anonymous

When I go back and plug into the original equation, I want to make sure I plug into the right variable.

- anonymous

which variable do i plug into and do i use the 5 or -3?

- anonymous

Okay, when you do this kind of problem, it's not important which variable you solve for first. You picked y. That's fine.
What's not fine is that halfway through the problem, you started calling it x. Do you understand? You were solving for y, and then you randomly renamed it x. This will cause problems. You solved for y. Don't rename it and there won't be any confusion.
So now you know y, so obviously that's what you can substitute in for.

- slaaibak

lol

- anonymous

sorry and yes we know 2 answer to y so then which one would you substitute for x?

- anonymous

Now, I understand that it's a little confusing that you get two answers for y. Try not to be confused by it. It just means that there are two possible answers to the question. One is when y=5 and the other is when y = -3. Whichever one you pick, you'll get an x value that goes along with that y value.

- anonymous

ok i chose 5 and plugged it into x=4y-8 and i got 12

- anonymous

Good =)
So one possible solution is:
x=12 y =5
Understand? Find the other possible solution.

- anonymous

the other possible solution is 55?

- anonymous

Woah there. Where'd 55 come from? You makin' guesses or somethin'?

- anonymous

whoops is it 63?

- anonymous

wait ! lol sorry im using the wrong equation

- anonymous

I have no idea what you're doing. Lol.

- anonymous

x= -20 ?

- anonymous

That's not wrong... but it's not a complete answer.

- anonymous

but isnt it x= 12, -20

- anonymous

The question asks you what the two variables are. The two variables are x and y. It turns out this problem has two possible answers, but a good answer should give me an x value and a y value.

- anonymous

but theres 2 x and y values

- anonymous

Ooooh, goodness. How to explain this...

- anonymous

lol i dont know what should i do? should i just leave 2 values for both variables?

- anonymous

Kind of.

- anonymous

Alright, stop worrying so much about the correct answer and let's just consider the question, okay?

- anonymous

ok

- anonymous

The question is talking about a couple of numbers. We called them x and y. And it told us something about those numbers.

- anonymous

It told us that that their product is 60. We wrote an equation about that. And it told us that one number was 8 less than 4 times the other. We wrote an equation about that.

- slaaibak

Two solution sets. (5,12) and (-3, 20) That's all you need to know

- anonymous

And we're just trying to figure out two numbers that those things are true for.

- anonymous

Right?

- anonymous

right

- anonymous

So our answer should be two numbers. We happened to name them x and y, so our answer will look like
x=
y=

- anonymous

Well, it turns out, there's more than one possible pair of numbers.

- anonymous

yup so i just leave those 2 answers?

- anonymous

Right. And what are those two answers?

- anonymous

y= 5, -3
x= 12, -20

- anonymous

mmmm, I don't like how you wrote that.

- anonymous

why?

- anonymous

Is x=5 y = -20 a solution?

- anonymous

Try plugging it in if you need to check.

- anonymous

no i put y=5

- anonymous

and x= -20

- anonymous

Sorry, my mistake.
Is y = 5 x=-20 a solution?

- anonymous

That's what I meant to ask.

- anonymous

wait no it isnt i just tried it out

- anonymous

Oh my. =(

- anonymous

Okay so... is y=5 still good?

- anonymous

It's not good when x=-20, we decided.

- anonymous

yes

- anonymous

Alright, why is it still good?

- anonymous

because when we plug it in -20=4(5)-8
it gives us 12 which is not equal to -20

- anonymous

Okay, that tells me why
y=5 x=-20 is not a solution.
Is y =5 bad in general then?
Is x=-20 bad?

- anonymous

yes its bad the -20

- anonymous

wait no the 5 is bad

- anonymous

if we plug in -3 it will work

- anonymous

Ahhhhhh
my point isn't that they are bad COMPLETELY.
My point is just that they don't work TOGETHER.

- anonymous

oh sorry lol so i can just leave both numbers?

- anonymous

Your answer really needs to be two numbers that work together. What are two numbers that work together?

- anonymous

-3 and -20

- anonymous

Great. That's one answer.

- anonymous

As a SECOND. SEPARATE answer

- anonymous

you could do 5 and 12

- anonymous

So, to clarify, you wrote
y = 5, -3
x = 12, -20
Which doesn't make it obvious which number goes with which.
If you write it this way, it's much more clear
y=5 x=12, and
y=-3 x=-20

- anonymous

I know it probably seems unimportant, but writing it the first way really shows that you don't understand the question or your answer.

- anonymous

no it does seem important, thanks so much once again for your help it really means alot =D
but i must go because its getting pretty late here

- anonymous

Well, if the problem was written as an actual real-life problem, it would be easier to explain why it was important. For example, maybe these numbers we're trying to solve for are
x=pack of skittles purchased
y = number of snickers bars purchased
My answer would say something like "Oh, you EITHER bought 5 packs of skittles and 12 snickers bars OOOOR you bought -3 packs of skittles and -20 snickers bars"
(shhh please ignore the fact that you can't buy a negative numer of snicker bars)
Your answer would say something like, "You bought 5 packs of skittles and -3 packs of skittles. And the number of snickers bars you bought is 12. And also -20."

- anonymous

oh yeahhh! i like how you related it to real life lol and yeah so it really is possible to have negatives in our answer as long as it works together

- anonymous

Yeah, we can have negatives =)
If we're solving real life problems, a lot of times we'll get negative answers. Those negative answers might make sense, or they might not and we might ignore them.

- anonymous

For example, if our problem was about money, then the positive answer might mean we made money and the negative answer might mean we lost money.
However, if the problem we're solving is about how many children someone has and we got one negative answer and one positive answer, well we'd take the positive one and ignore the negative one because there is no way to have negative children.

- anonymous

yeah i see where you're going at and what you'tr trying to say. im sorry to end this convo but i have to leave to get some sleep because im up early in the morning tomorrow

- anonymous

Goodnight. =)

- anonymous

goodnight and thanks so much once again! you have been an amazing help!

- anonymous

My pleasure =)

Looking for something else?

Not the answer you are looking for? Search for more explanations.