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catgirl17

  • 3 years ago

find the numbers of permutations 10P6

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  1. jim_thompson5910
    • 3 years ago
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    do you have any ideas on the first step?

  2. catgirl17
    • 3 years ago
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    \[_{10} P _{6}\]

  3. catgirl17
    • 3 years ago
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    no

  4. jim_thompson5910
    • 3 years ago
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    Are you familiar with the permutation formula?

  5. catgirl17
    • 3 years ago
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    no

  6. jim_thompson5910
    • 3 years ago
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    If not, the permutation formula is n P r = (n!)/((n-r)!) where n! means n! = n*(n-1)*(n-2)*...*3*2*1 For example: 6! = 6*5*4*3*2*1

  7. jim_thompson5910
    • 3 years ago
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    So in our case, 10 P 6 is 10 P 6 = (10!)/((10-6)!) since n = 10 and r = 6

  8. jim_thompson5910
    • 3 years ago
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    Can you take it from here or do you need more help?

  9. catgirl17
    • 3 years ago
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    yes i need more help please

  10. jim_thompson5910
    • 3 years ago
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    (10!)/((10-6)!) will become (10!)/(4!) since 10-6 = 4

  11. jim_thompson5910
    • 3 years ago
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    Then you expand out 10! like so 10*9*8*7*6*5*4! We stop at 4 because the "4!" terms will cancel So (10!)/(4!) turns into (10*9*8*7*6*5*4!)/(4!) and the "4!" terms will cancel leaving us with 10*9*8*7*6*5

  12. jim_thompson5910
    • 3 years ago
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    Last step is to multiply out 10*9*8*7*6*5 to get your answer

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