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catgirl17 Group Title

find the numbers of permutations 10P6

  • 2 years ago
  • 2 years ago

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  1. jim_thompson5910 Group Title
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    do you have any ideas on the first step?

    • 2 years ago
  2. catgirl17 Group Title
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    \[_{10} P _{6}\]

    • 2 years ago
  3. catgirl17 Group Title
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    no

    • 2 years ago
  4. jim_thompson5910 Group Title
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    Are you familiar with the permutation formula?

    • 2 years ago
  5. catgirl17 Group Title
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    no

    • 2 years ago
  6. jim_thompson5910 Group Title
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    If not, the permutation formula is n P r = (n!)/((n-r)!) where n! means n! = n*(n-1)*(n-2)*...*3*2*1 For example: 6! = 6*5*4*3*2*1

    • 2 years ago
  7. jim_thompson5910 Group Title
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    So in our case, 10 P 6 is 10 P 6 = (10!)/((10-6)!) since n = 10 and r = 6

    • 2 years ago
  8. jim_thompson5910 Group Title
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    Can you take it from here or do you need more help?

    • 2 years ago
  9. catgirl17 Group Title
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    yes i need more help please

    • 2 years ago
  10. jim_thompson5910 Group Title
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    (10!)/((10-6)!) will become (10!)/(4!) since 10-6 = 4

    • 2 years ago
  11. jim_thompson5910 Group Title
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    Then you expand out 10! like so 10*9*8*7*6*5*4! We stop at 4 because the "4!" terms will cancel So (10!)/(4!) turns into (10*9*8*7*6*5*4!)/(4!) and the "4!" terms will cancel leaving us with 10*9*8*7*6*5

    • 2 years ago
  12. jim_thompson5910 Group Title
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    Last step is to multiply out 10*9*8*7*6*5 to get your answer

    • 2 years ago
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