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tanvidais13
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Imagine, there's a cubic graph which has already been plotted, and imagine they want you to graphically plot it's inverse. In which line do you have to reflect it??
 2 years ago
 2 years ago
tanvidais13 Group Title
Imagine, there's a cubic graph which has already been plotted, and imagine they want you to graphically plot it's inverse. In which line do you have to reflect it??
 2 years ago
 2 years ago

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Aadarsh Group TitleBest ResponseYou've already chosen the best response.1
Do u mean this graph?
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.1
dw:1337492052470:dw
 2 years ago

tanvidais13 Group TitleBest ResponseYou've already chosen the best response.1
I mean, literally ANY graph :P
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.1
So, is my graph correct?
 2 years ago

tanvidais13 Group TitleBest ResponseYou've already chosen the best response.1
yeahh, i guess :P wait is this the cubic graph, or the line in which it hsa to be reflected in, or the reflected cubic graph?? i'm confused :P
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
The graph of inverse of any function is just the same graph that is its mirror image about the 'y=x' line  basically flipped about the 'diagonal'.
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
(ofcourse provided that the function if bijective and the inverse exists)
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
Yeah, and so in you y=x^3 graph, the curve of the inverse is simply flipped about 'y=x' something like this: (I think I need to draw a new curve): dw:1337492674235:dw
 2 years ago

apoorvk Group TitleBest ResponseYou've already chosen the best response.1
dw:1337492883274:dw That's^^ the inverse of y=x^3, or basically the graph of y=x^(1/3) (in black)
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.1
Yeah. @apoorvk is right. Yesterday, our maths sir taught this. Thanks Tanvi for helping me to revise my concepts. :P
 2 years ago
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