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Assume quadratic \(\Huge ax^2+bx+c=0\) has roots \(\Huge \alpha\) and \(\Huge \beta\)

Then, \((x-\alpha)(x-\beta)=0\), which is an alternate formulation of our equation
\(ax^2+bx+c=0\)

In other words,
\(\Large -(\alpha+\beta)=\frac{b}{a}\)
and
\(\Large\alpha\beta=\frac{c}{a}\)

And that is how you solve the quadratic by looking at the roots.

vieta's formula?

Probably. It's probably a obscure thing I haven't heard of. Like transmauchen.

lol, you havent heard of but you know how to it...?

Hey, I'm a genius trololol

Hey nice explanation:)

Thanks :)

yw:)

Interesting. Sadly, I can't make heads or tails of it.

Eh? what part do you not understand?

@roadjester , it's merely a solution to the quadratic by reverse analysis.

Nice work,
Thanks