apoorvk
  • apoorvk
APOORIDDLE! \[\large \mathsf {\color{crimson}{APOORIDDLE}} \color{crimson}{\text{#2}} \] Find out the next two bases in the tower sequence below: 1 11 21 1211 3112 211213 312213 212223 Also, what happens to the sequence ultimately?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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apoorvk
  • apoorvk
[If you've come across something like this before, please wait before posting your solution to give others a fair chance to think, or send a PM :) ]
anonymous
  • anonymous
Same old same old :)
apoorvk
  • apoorvk
Okay @asnaseer gets this problem, and gets this!!! --> \[\huge \color{gold}{★★★}\]

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More answers

anonymous
  • anonymous
114213 ...
apoorvk
  • apoorvk
yeah same old @FoolForMath , but not everyone was here since eternity - plus I modified the original one a bit.
asnaseer
  • asnaseer
thx apoorvk - now if only I could take those gold stars and pin them on my virtual image :D
anonymous
  • anonymous
What about my gold star?
apoorvk
  • apoorvk
@diyadiya gets both parts right next. For her ---> \[\huge \color {gold}{★★}\] @FoolForMath , you are already a genius, you have come across this plentiful times before, plus you posted only one part :D. Still, well deserving, for you--> \[\large \color {gold}{★★}\]
anonymous
  • anonymous
lol, Thanks! :D
Diyadiya
  • Diyadiya
\[\large \color{gold}{ Thanks :) }\]
PaxPolaris
  • PaxPolaris
shouldn't the 4th number in thr sequence be 1112 ????
apoorvk
  • apoorvk
\[\huge{\color{red}{\normalsize\text{W}}\color{orange}{\normalsize\text{e}}\color{#9c9a2e}{\normalsize\text{l}}\color{green}{\normalsize\text{c}}\color{blue}{\normalsize\text{o}}\color{purple}{\normalsize\text{m}}\color{purple}{\normalsize\text{e}}\color{red}{\normalsize\text{}}\color{orange}{\normalsize\text{}}}\]
apoorvk
  • apoorvk
@PaxPolaris - maybe. won't matter though.
apoorvk
  • apoorvk
You can assume that as '1112' as well - same stuff.
apoorvk
  • apoorvk
Nobody else? It's SUNDAY folks!
PaxPolaris
  • PaxPolaris
114213 31121314 41122314 31221324 21322314 21322314 21322314
apoorvk
  • apoorvk
Wonderfullll!!! Late but nevertheless for @PaxPolaris a very well deserved --> \[\huge \color {gold}{★★}\]
apoorvk
  • apoorvk
So, you see the tower stabilises at a point, and it looks like- 1 11 21 1211 3112 211213 312213 212223 114213 31121314 41122314 31221324 21322314 21322314 21322314 21322314 21322314 21322314 . . . . . . A bit like the Empire State Building maybe? ;)
anonymous
  • anonymous
deja vu that strange feeling you get when you think you've been there before
anonymous
  • anonymous
deja vu that strange feeling you get when you think you've been there before
apoorvk
  • apoorvk
Lol
KingGeorge
  • KingGeorge
A (very) similar problem: What's the next row in this pattern? 1 11 21 1211 111221 312211 13112221 1113213211
apoorvk
  • apoorvk
31131211131221
apoorvk
  • apoorvk
I am right, right?
KingGeorge
  • KingGeorge
Looks correct to me
apoorvk
  • apoorvk
It's basically the in sequence - not taking all occurences in the same line at once.
KingGeorge
  • KingGeorge
Exactly. Although I wonder if it ever starts repeating.
KingGeorge
  • KingGeorge
Or at least gets a repeating pattern.
apoorvk
  • apoorvk
I don't think so.. let's see. Won't stabilise according to me... let's find out.
KingGeorge
  • KingGeorge
Some repeating patterns sounds plausible, but I also doubt it would ever fully repeat.
apoorvk
  • apoorvk
In fact it con't even converge. nah.
apoorvk
  • apoorvk
This one is less of tower, and more of a mountain! (with decreasing slope)
KingGeorge
  • KingGeorge
Nice afternoon hike then :)
apoorvk
  • apoorvk
Haha..:D
lgbasallote
  • lgbasallote
this seems familiar @apoorvk =_=
apoorvk
  • apoorvk
Don't worry, it's not ripped off from you - and this one is modified a bit ;)
apoorvk
  • apoorvk
**has been
lgbasallote
  • lgbasallote
gooood =_=

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