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cgian66
another one \[(27m{3}/{2}n^-6)^2/3\] the last exponent is 2/3
use the properties of exponents to simplify the expression
\[(=3^3m^{\frac{3}{2}}n^{-6})^{\frac{2}{3}}\]Take the cube root of each factor inside the parentheses (divide each exponent by 3)\[=(3m^{\frac{1}{2}}n^{-2})^{2}\]then, square each factor (multiply each exponent by 2)\[=3^2mn^{-4}\]\[=9mn^{-4}\]