## anonymous 4 years ago another one $(27m{3}/{2}n^-6)^2/3$ the last exponent is 2/3

1. anonymous

grrr (27m^3/2n^-6)^2/3

2. anonymous

|dw:1337538438544:dw|

3. anonymous

use the properties of exponents to simplify the expression

4. anonymous

$(=3^3m^{\frac{3}{2}}n^{-6})^{\frac{2}{3}}$Take the cube root of each factor inside the parentheses (divide each exponent by 3)$=(3m^{\frac{1}{2}}n^{-2})^{2}$then, square each factor (multiply each exponent by 2)$=3^2mn^{-4}$$=9mn^{-4}$