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cgian66

  • 3 years ago

another one \[(27m{3}/{2}n^-6)^2/3\] the last exponent is 2/3

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  1. cgian66
    • 3 years ago
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    grrr (27m^3/2n^-6)^2/3

  2. cgian66
    • 3 years ago
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    |dw:1337538438544:dw|

  3. cgian66
    • 3 years ago
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    use the properties of exponents to simplify the expression

  4. agdgdgdgwngo
    • 3 years ago
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    \[(=3^3m^{\frac{3}{2}}n^{-6})^{\frac{2}{3}}\]Take the cube root of each factor inside the parentheses (divide each exponent by 3)\[=(3m^{\frac{1}{2}}n^{-2})^{2}\]then, square each factor (multiply each exponent by 2)\[=3^2mn^{-4}\]\[=9mn^{-4}\]

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