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Suppose you roll an eightsided die two times hoping to get two numbers whose sum is even. What is the sample space? How many favorable outcomes are there?
 one year ago
 one year ago
Suppose you roll an eightsided die two times hoping to get two numbers whose sum is even. What is the sample space? How many favorable outcomes are there?
 one year ago
 one year ago

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acrossBest ResponseYou've already chosen the best response.1
This is not a computer science question. I recommend you ask it in the Mathematics section.
 one year ago

agdgdgdgwngoBest ResponseYou've already chosen the best response.2
Combinatorics is computersciency enough.
 one year ago

acrossBest ResponseYou've already chosen the best response.1
If you do a little number theory, you will realize that the sum of two even numbers and two odd numbers is always even. Therefore, you are looking at all the possibilities of obtaining two numbers of the same parity. The sample space of an 8sided die rolled twice has a size of 64 outcomes. However, we are only interested in a specific subset of this sample space, namely, of numbers with the same parity. On your first roll, you can get anything, but you have two options: either an odd number or an even number. On your second roll, you are only interested in a number whose parity matches that of the first number. In the case of an 8sided die, you will have 4 options. Hence, it is easy to see that you will have a sample space of 16 favorable outcomes.
 one year ago

acrossBest ResponseYou've already chosen the best response.1
Oh, yes, I forgot to add the even parity. Hence, 16+16.
 one year ago
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