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mahmit2012
Group Title
Q5
find a best bound of y for x>=0: a<=y=<b a,b=? if
y'=dy/dx=1/(x^2+y^2) x>0 ; y(0)=1
 2 years ago
 2 years ago
mahmit2012 Group Title
Q5 find a best bound of y for x>=0: a<=y=<b a,b=? if y'=dy/dx=1/(x^2+y^2) x>0 ; y(0)=1
 2 years ago
 2 years ago

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mahmit2012 Group TitleBest ResponseYou've already chosen the best response.1
dw:1337540828547:dw
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
1 <= y <= infinity ??
 2 years ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.1
sorry that is more compact than that you find.
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
is it between 1.5 and 2 ??
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
both negative and positive?
 2 years ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.1
f(0)=1 so 1 belonging to interval.
 2 years ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.1
y'>0 in conclude y is a ascending function and because of y(0)=1 we can show for x>=0 ; y>=1 so a=1 for get a reasonable upper bound of y or b:dw:1337618744074:dw
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
I didn't have a clue http://www.hostsrv.com/webmaa/app1/MSP/webm1001/IntegralCurves
 2 years ago

mahmit2012 Group TitleBest ResponseYou've already chosen the best response.1
yes there are many ways to solve y'=f(x,y) but there is no always a close function for each question. In this case or yours we can only find approximately curve with numerical calculation.
 2 years ago
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