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Find dy/dx: y=e^(5-3lnx)

Mathematics
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use chain rule
I dont think so he know the chain rule let's help out :)
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so this would be 5/(3lnx)?

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Other answers:

nope answer would be : -3/x(e^5-3lnx)
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could you please show me the steps, i am confused how you get that..
@muhe Don't just give the answer. It is against our CoC. Thanks for understanding.
okay sorry for that I thought he is asking only the answer..
\[y=e^{f(x)} => y'=f'(x) e^{f(x)} \]
This right here will work every time for something in the form of \[y=e^{f(x)}\]
U differentiate the power of the e first and then multiply it with the function that is how u differentiate the power of the e..
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sorry, my battery just died
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so, in this case the derivative of 5
\[y'=(5-3 \ln(x))'e^{5-3\ln(x)}\] using the rule I wrote down
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the derivative of 5-3lnx would be -3* 1/x ?
Yes! So what is y'?
yes exactly
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so y' would be -3/x * e^(5-3lnx)
:) Great job everyone!
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thank you =D now I get that !

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