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S

  • 2 years ago

Find dy/dx: y=e^(5-3lnx)

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  1. lgbasallote
    • 2 years ago
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    use chain rule

  2. muhe
    • 2 years ago
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    I dont think so he know the chain rule let's help out :)

  3. S
    • 2 years ago
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    so this would be 5/(3lnx)?

  4. muhe
    • 2 years ago
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    nope answer would be : -3/x(e^5-3lnx)

  5. S
    • 2 years ago
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    could you please show me the steps, i am confused how you get that..

  6. myininaya
    • 2 years ago
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    @muhe Don't just give the answer. It is against our CoC. Thanks for understanding.

  7. muhe
    • 2 years ago
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    okay sorry for that I thought he is asking only the answer..

  8. myininaya
    • 2 years ago
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    \[y=e^{f(x)} => y'=f'(x) e^{f(x)} \]

  9. myininaya
    • 2 years ago
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    This right here will work every time for something in the form of \[y=e^{f(x)}\]

  10. muhe
    • 2 years ago
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    U differentiate the power of the e first and then multiply it with the function that is how u differentiate the power of the e..

  11. S
    • 2 years ago
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    sorry, my battery just died

  12. S
    • 2 years ago
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    so, in this case the derivative of 5

  13. myininaya
    • 2 years ago
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    \[y'=(5-3 \ln(x))'e^{5-3\ln(x)}\] using the rule I wrote down

  14. S
    • 2 years ago
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    the derivative of 5-3lnx would be -3* 1/x ?

  15. myininaya
    • 2 years ago
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    Yes! So what is y'?

  16. muhe
    • 2 years ago
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    yes exactly

  17. S
    • 2 years ago
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    so y' would be -3/x * e^(5-3lnx)

  18. myininaya
    • 2 years ago
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    :) Great job everyone!

  19. S
    • 2 years ago
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    thank you =D now I get that !

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