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muhe
 2 years ago
Best ResponseYou've already chosen the best response.1I dont think so he know the chain rule let's help out :)

muhe
 2 years ago
Best ResponseYou've already chosen the best response.1nope answer would be : 3/x(e^53lnx)

S
 2 years ago
Best ResponseYou've already chosen the best response.0could you please show me the steps, i am confused how you get that..

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1@muhe Don't just give the answer. It is against our CoC. Thanks for understanding.

muhe
 2 years ago
Best ResponseYou've already chosen the best response.1okay sorry for that I thought he is asking only the answer..

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1\[y=e^{f(x)} => y'=f'(x) e^{f(x)} \]

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1This right here will work every time for something in the form of \[y=e^{f(x)}\]

muhe
 2 years ago
Best ResponseYou've already chosen the best response.1U differentiate the power of the e first and then multiply it with the function that is how u differentiate the power of the e..

S
 2 years ago
Best ResponseYou've already chosen the best response.0so, in this case the derivative of 5

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1\[y'=(53 \ln(x))'e^{53\ln(x)}\] using the rule I wrote down

S
 2 years ago
Best ResponseYou've already chosen the best response.0the derivative of 53lnx would be 3* 1/x ?

S
 2 years ago
Best ResponseYou've already chosen the best response.0so y' would be 3/x * e^(53lnx)

myininaya
 2 years ago
Best ResponseYou've already chosen the best response.1:) Great job everyone!

S
 2 years ago
Best ResponseYou've already chosen the best response.0thank you =D now I get that !
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