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Find dy/dx: y=e^(53lnx)



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lgbasallote
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use chain rule

muhe
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I dont think so he know the chain rule let's help out :)

S
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so this would be 5/(3lnx)?

muhe
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nope answer would be : 3/x(e^53lnx)

S
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could you please show me the steps, i am confused how you get that..

myininaya
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@muhe Don't just give the answer. It is against our CoC. Thanks for understanding.

muhe
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okay sorry for that I thought he is asking only the answer..

myininaya
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\[y=e^{f(x)} => y'=f'(x) e^{f(x)} \]

myininaya
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This right here will work every time
for something in the form of \[y=e^{f(x)}\]

muhe
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U differentiate the power of the e first and then multiply it with the function that is how u differentiate the power of the e..

S
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sorry, my battery just died

S
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so, in this case the derivative of 5

myininaya
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\[y'=(53 \ln(x))'e^{53\ln(x)}\]
using the rule I wrote down

S
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the derivative of 53lnx would be 3* 1/x ?

myininaya
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Yes!
So what is y'?

muhe
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yes exactly

S
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so y' would be 3/x * e^(53lnx)

myininaya
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:)
Great job everyone!

S
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thank you =D now I get that !