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S
 4 years ago
Find dy/dx: y=e^(53lnx)
S
 4 years ago
Find dy/dx: y=e^(53lnx)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I dont think so he know the chain rule let's help out :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so this would be 5/(3lnx)?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0nope answer would be : 3/x(e^53lnx)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0could you please show me the steps, i am confused how you get that..

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1@muhe Don't just give the answer. It is against our CoC. Thanks for understanding.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay sorry for that I thought he is asking only the answer..

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[y=e^{f(x)} => y'=f'(x) e^{f(x)} \]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1This right here will work every time for something in the form of \[y=e^{f(x)}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0U differentiate the power of the e first and then multiply it with the function that is how u differentiate the power of the e..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry, my battery just died

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so, in this case the derivative of 5

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[y'=(53 \ln(x))'e^{53\ln(x)}\] using the rule I wrote down

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the derivative of 53lnx would be 3* 1/x ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so y' would be 3/x * e^(53lnx)

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1:) Great job everyone!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thank you =D now I get that !
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