S
  • S
Find dy/dx: y=e^(5-3lnx)
Mathematics
schrodinger
  • schrodinger
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lgbasallote
  • lgbasallote
use chain rule
anonymous
  • anonymous
I dont think so he know the chain rule let's help out :)
S
  • S
so this would be 5/(3lnx)?

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anonymous
  • anonymous
nope answer would be : -3/x(e^5-3lnx)
S
  • S
could you please show me the steps, i am confused how you get that..
myininaya
  • myininaya
@muhe Don't just give the answer. It is against our CoC. Thanks for understanding.
anonymous
  • anonymous
okay sorry for that I thought he is asking only the answer..
myininaya
  • myininaya
\[y=e^{f(x)} => y'=f'(x) e^{f(x)} \]
myininaya
  • myininaya
This right here will work every time for something in the form of \[y=e^{f(x)}\]
anonymous
  • anonymous
U differentiate the power of the e first and then multiply it with the function that is how u differentiate the power of the e..
S
  • S
sorry, my battery just died
S
  • S
so, in this case the derivative of 5
myininaya
  • myininaya
\[y'=(5-3 \ln(x))'e^{5-3\ln(x)}\] using the rule I wrote down
S
  • S
the derivative of 5-3lnx would be -3* 1/x ?
myininaya
  • myininaya
Yes! So what is y'?
anonymous
  • anonymous
yes exactly
S
  • S
so y' would be -3/x * e^(5-3lnx)
myininaya
  • myininaya
:) Great job everyone!
S
  • S
thank you =D now I get that !

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