verify: sin(x+y)-sin(x-y)=2cosxsiny

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verify: sin(x+y)-sin(x-y)=2cosxsiny

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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cos(x+y)=cosxacosy-sinxsiny cos(x-y)=cosxcosy+sinxsiny addition produces 2cosxcosy
take the left hand side...do you know the formula for sin(x+y) and sin(x-y)?
Its an identity.

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Other answers:

i think so but i'm not sure
sin(x+y) = sinxcosy + sinycosx sin(x-y) = sinxcosy - sinycosx can you do it from here?
it looks familiar but i can't figure it out. is it one of the cosine identities?
no...you substitute those into your problem sin(x+y) - sin (x-y) = sinxcosy + cosxsiny - (sinxcosy - cosxsiny)
i'm still confused
with what?
how to do all of this in general
basically you memorize the identities...
i did not do anything fancy...all i did was substitute identities
oh ok
so regarding this problem...you're good?
not really...
sinxcosy + cosxsiny - (sinxcosy - cosxsiny) sinxcosy = cosxsiny - sinxcosy + cosxsiny
that's a + not an =
i don't understand what you did
i distributed the minus sign
oh ok i see
so you're good now?
yes thanks ^^

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