anonymous
  • anonymous
verify: sin(x+y)-sin(x-y)=2cosxsiny
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
cos(x+y)=cosxacosy-sinxsiny cos(x-y)=cosxcosy+sinxsiny addition produces 2cosxcosy
lgbasallote
  • lgbasallote
take the left hand side...do you know the formula for sin(x+y) and sin(x-y)?
anonymous
  • anonymous
Its an identity.

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anonymous
  • anonymous
i think so but i'm not sure
lgbasallote
  • lgbasallote
sin(x+y) = sinxcosy + sinycosx sin(x-y) = sinxcosy - sinycosx can you do it from here?
anonymous
  • anonymous
it looks familiar but i can't figure it out. is it one of the cosine identities?
lgbasallote
  • lgbasallote
no...you substitute those into your problem sin(x+y) - sin (x-y) = sinxcosy + cosxsiny - (sinxcosy - cosxsiny)
anonymous
  • anonymous
i'm still confused
lgbasallote
  • lgbasallote
with what?
anonymous
  • anonymous
how to do all of this in general
lgbasallote
  • lgbasallote
basically you memorize the identities...
lgbasallote
  • lgbasallote
i did not do anything fancy...all i did was substitute identities
anonymous
  • anonymous
oh ok
lgbasallote
  • lgbasallote
so regarding this problem...you're good?
anonymous
  • anonymous
not really...
lgbasallote
  • lgbasallote
sinxcosy + cosxsiny - (sinxcosy - cosxsiny) sinxcosy = cosxsiny - sinxcosy + cosxsiny
lgbasallote
  • lgbasallote
that's a + not an =
anonymous
  • anonymous
i don't understand what you did
lgbasallote
  • lgbasallote
i distributed the minus sign
anonymous
  • anonymous
oh ok i see
lgbasallote
  • lgbasallote
so you're good now?
anonymous
  • anonymous
yes thanks ^^

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