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How would you draw a cylinder for the shell method for the region that is enclosed by x = pi/2, x = pi/2 and y = cosx?
This is rotated about y = 1.
 one year ago
 one year ago
How would you draw a cylinder for the shell method for the region that is enclosed by x = pi/2, x = pi/2 and y = cosx? This is rotated about y = 1.
 one year ago
 one year ago

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QRAwarriorBest ResponseYou've already chosen the best response.0
@FoolForMath @myininaya @experimentX @shivam_bhalla @amistre64 @Zarkon @Hero Anyone?
 one year ago

akamushiBest ResponseYou've already chosen the best response.0
the definite integrand of f(x)=cosx from pi/2 to pi/2 sinx from pi/2 to pi/2 = 1(1)=2
 one year ago

QRAwarriorBest ResponseYou've already chosen the best response.0
I do not want the answer. @akamushi
 one year ago

QRAwarriorBest ResponseYou've already chosen the best response.0
@FoolForMath @myininaya @experimentX @shivam_bhalla @amistre64 @Zarkon @Hero Anyone?
 one year ago

QRAwarriorBest ResponseYou've already chosen the best response.0
@FoolForMath @myininaya @experimentX @shivam_bhalla @amistre64 @Zarkon @Hero Anyone?
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
@lgbasallote lol jk...idk shell using trig functions
 one year ago

QRAwarriorBest ResponseYou've already chosen the best response.0
The height would be 2cosx, and the radius would be cosx  (1)?
 one year ago

QRAwarriorBest ResponseYou've already chosen the best response.0
ie. h = 2y r = y  (1) ?
 one year ago

QRAwarriorBest ResponseYou've already chosen the best response.0
dw:1337558085638:dw
 one year ago

QRAwarriorBest ResponseYou've already chosen the best response.0
The height (which are the horizontal lines of the cylinder) would be given by h = 2cosx? And the radius would be given by r = cos(x)  (1)?
 one year ago

QRAwarriorBest ResponseYou've already chosen the best response.0
Wait, I think the height would be: h = 2x, due to symmetry
 one year ago

QRAwarriorBest ResponseYou've already chosen the best response.0
dw:1337558202025:dw
 one year ago

QRAwarriorBest ResponseYou've already chosen the best response.0
So then, radius is r = cos(x)  (1) for sure, right?
 one year ago

QRAwarriorBest ResponseYou've already chosen the best response.0
And I can restate that cos(x) as y So then, r = y +1, h = 2x = 2arccos(y), I believe.
 one year ago

PROSSBest ResponseYou've already chosen the best response.0
now you are on the right track.
 one year ago

PROSSBest ResponseYou've already chosen the best response.0
if you are familiar with winplot, you can make a nice 3d representation.
 one year ago

QRAwarriorBest ResponseYou've already chosen the best response.0
@shivam_bhalla! Yes you finally came.
 one year ago

QRAwarriorBest ResponseYou've already chosen the best response.0
dw:1337558589994:dw
 one year ago

QRAwarriorBest ResponseYou've already chosen the best response.0
I have one question for either of you: I drew a vertical line from the xaxis to the function cos(x). Can that generically be represented as y?
 one year ago

shivam_bhallaBest ResponseYou've already chosen the best response.0
@QRAwarrior , try this http://openstudy.com/updates/4fb44286e4b05565342a2a03 You will find it a lot more helpful :) The answer to your question you asked before is yes
 one year ago

amistre64Best ResponseYou've already chosen the best response.3
x = pi/2, x = pi/2 and y = cosxdw:1337561871090:dw
 one year ago

amistre64Best ResponseYou've already chosen the best response.3
dw:1337562804283:dw
 one year ago

QRAwarriorBest ResponseYou've already chosen the best response.0
Ok so it is: h = x y = cosx  (1)
 one year ago

amistre64Best ResponseYou've already chosen the best response.3
we only need half of this, then double the results height is a measure of arccos(y) radius is from from 1 to 2 by perspective \[2*2pi\int_{0}^{1}(y+1)*\cos^{1}(y)\ dy\]
 one year ago

QRAwarriorBest ResponseYou've already chosen the best response.0
I think I came up with this a few posts back
 one year ago

amistre64Best ResponseYou've already chosen the best response.3
height is a function of x; y=cos(x) arccos(y) = x = height
 one year ago

QRAwarriorBest ResponseYou've already chosen the best response.0
 Ok consider this question: Find the length of y^2 = x^3 from (0,0) to (4,8) I know the formula for arclength, but I end up getting this: dw:1337563218324:dw
 one year ago

QRAwarriorBest ResponseYou've already chosen the best response.0
dw:1337563244465:dw
 one year ago

QRAwarriorBest ResponseYou've already chosen the best response.0
How the heck can you resolve the radical when you have: dw:1337563293983:dw As your argument?
 one year ago

amistre64Best ResponseYou've already chosen the best response.3
have you tried looking at it form both forms? \[\sqrt{1+(x')^2}\ or\ \sqrt{1+(y')^2}\]
 one year ago

QRAwarriorBest ResponseYou've already chosen the best response.0
No. I think I will try the other form, BUT the problem is that I am not sure whether to pick the POSITIVE root or the NEGATIVE root..
 one year ago

amistre64Best ResponseYou've already chosen the best response.3
for the most part, i think you stick with the positive root
 one year ago

QRAwarriorBest ResponseYou've already chosen the best response.0
Why do you say "most part"
 one year ago

amistre64Best ResponseYou've already chosen the best response.3
distance tends to be a measure in absolute value, so the positive root seems most apt
 one year ago

QRAwarriorBest ResponseYou've already chosen the best response.0
WOW! I just realized how EASY it is doing it wrt x.
 one year ago

QRAwarriorBest ResponseYou've already chosen the best response.0
dw:1337563549037:dw
 one year ago

QRAwarriorBest ResponseYou've already chosen the best response.0
Easy Usub. Thanks a lot amistre64. What level of education is your mathematics?
 one year ago

amistre64Best ResponseYou've already chosen the best response.3
i dunno what level it is, im guessing its at least on a 3rd grade level ;)
 one year ago

QRAwarriorBest ResponseYou've already chosen the best response.0
Ok anyways, thanks for your help
 one year ago

amistre64Best ResponseYou've already chosen the best response.3
youre welcome. Levelwise is difficult since im self taught for the most part of this stuff
 one year ago
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