Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

ERoseM

  • 3 years ago

Use the definition of the derivative to find f prime(x) for: f(x)= x^2-2x

  • This Question is Closed
  1. ERoseM
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Please help!

  2. akamushi
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    2x-2

  3. mathdood
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    use nx^n-1 but yeah akamushi is right

  4. dpaInc
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    if you're going to use the definition you'll need to find the limit of the difference quotient: \[\large \lim_{h \rightarrow 0} \frac {f(x+h) - f(x)}{h}\] \[\large \lim_{h \rightarrow 0} \frac {[(x+h)^2-2(x+h)] - [x^2-2x]}{h}\] \[\large \lim_{h \rightarrow 0} \frac {x^2+2xh+h^2-2x-2h - x^2+2x}{h}\] \[\large \lim_{h \rightarrow 0} \frac {2xh+h^2-2h}{h}\] \[\large \lim_{h \rightarrow 0} \frac {h(2x+h-2)}{h}\] \[\large \lim_{h \rightarrow0} 2x+h-2\] \[\large =2x+0-2 = 2x-2\]

  5. ERoseM
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Thank you, this help me a lot more.

  6. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy