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## anonymous 4 years ago Use the definition of the derivative to find f prime(x) for: f(x)= x^2-2x

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1. anonymous

Please help!

2. anonymous

2x-2

3. anonymous

use nx^n-1 but yeah akamushi is right

4. anonymous

if you're going to use the definition you'll need to find the limit of the difference quotient: $\large \lim_{h \rightarrow 0} \frac {f(x+h) - f(x)}{h}$ $\large \lim_{h \rightarrow 0} \frac {[(x+h)^2-2(x+h)] - [x^2-2x]}{h}$ $\large \lim_{h \rightarrow 0} \frac {x^2+2xh+h^2-2x-2h - x^2+2x}{h}$ $\large \lim_{h \rightarrow 0} \frac {2xh+h^2-2h}{h}$ $\large \lim_{h \rightarrow 0} \frac {h(2x+h-2)}{h}$ $\large \lim_{h \rightarrow0} 2x+h-2$ $\large =2x+0-2 = 2x-2$

5. anonymous

Thank you, this help me a lot more.

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