anonymous
  • anonymous
determine the limit algebraically, it it exists PICTURE TO FOLLOW
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
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anonymous
  • anonymous
humm...i believe you do the LCD of this fraction, then plug in the limit once you simplify...
anonymous
  • anonymous
im still confused

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Mertsj
  • Mertsj
\[\lim \frac{\frac{1}{x+5}-\frac{1}{5}}{x}\times\frac{5(x+5)}{5(x+5)}=\frac{5-(x+5)}{5x(x+5)}=\frac{-x}{5x(x+5)}\]
Mertsj
  • Mertsj
\[\lim \frac{-1}{5(x+5)}\] Now take the limit by replacing x with 0
anonymous
  • anonymous
-1/25?
anonymous
  • anonymous
correct. so with limits, all you have to do is simplify the fraction, then when you cant simplify anymore, plug in your limit for whatever variable you have and that should be your answer. with limits at infinity its a bit different, but no worries, you can conquer those too!
anonymous
  • anonymous
alright thanks you guys!
anonymous
  • anonymous
no worries man

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