S
  • S
An object is thrown up from a height of 160 feet. Its velocity at t is v(t)=-32t+24 ft/ sec a) how high will it go? b) with what velocity will it hit the ground?
Mathematics
chestercat
  • chestercat
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
max height is at the vertex. use \(t=-\frac{b}{2a}\) to find it
anonymous
  • anonymous
oh but first you need the equation. it is \[h(t)=-16t^2+v_0t+h_0\] in your case \(h_0=160\) and \(v_0=\) hmm confused. what is the initial velocity?
anonymous
  • anonymous
oh it is 24, so your equation is \[h(t)=-16t^2+24t+160\] max when \(t=\frac{24}{32}=\frac{3}{4}\) replace \(t\) by \(\frac{3}{4}\) to find the max height

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

S
  • S
thank you

Looking for something else?

Not the answer you are looking for? Search for more explanations.