Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

S

An object is thrown up from a height of 160 feet. Its velocity at t is v(t)=-32t+24 ft/ sec a) how high will it go? b) with what velocity will it hit the ground?

  • one year ago
  • one year ago

  • This Question is Closed
  1. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    max height is at the vertex. use \(t=-\frac{b}{2a}\) to find it

    • one year ago
  2. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    oh but first you need the equation. it is \[h(t)=-16t^2+v_0t+h_0\] in your case \(h_0=160\) and \(v_0=\) hmm confused. what is the initial velocity?

    • one year ago
  3. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    oh it is 24, so your equation is \[h(t)=-16t^2+24t+160\] max when \(t=\frac{24}{32}=\frac{3}{4}\) replace \(t\) by \(\frac{3}{4}\) to find the max height

    • one year ago
  4. S
    Best Response
    You've already chosen the best response.
    Medals 0

    thank you

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.