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Who <333333333333s communnicaaatioooooooooon????????? How many phone numbers are possible for one area code if the first four numbers are 202-1, in that order, and the last three numbers are1-7-8 in any order?

Mathematics
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I think it is 3!
There are 7 digits total. The first 4 are locked in at 202-1 So there are 7-4 = 3 digits left The last three numbers are 1-7-8 in any order and there are 3! = 3*2*1 = 6 ways to order them So there are 1*6 = 6 different phone numbers.
Also for this question: Juan and Andrew are planning the schedule for a softball tournament. If there are 6 teams, how many different pairings could they make for the first tournament game? Is the answer to this one^^^^^ 6! which is 720 different pairings????? thank you got ur help!

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Other answers:

SimplyC(6,2)
There are 6 teams to choose for the first slot (say the "home" slot) and 6-1 = 5 teams to choose for the second ("away/visitor") slot So there are 6*5 = 30 different ways to do this.
oh so it's 30 instead for the answer to question number 2?
If it's all being played on one field, then order doesn't matter, so you would divide by 2 to avoid the double counting.

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