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lilai3

  • 2 years ago

Who <333333333333s communnicaaatioooooooooon????????? How many phone numbers are possible for one area code if the first four numbers are 202-1, in that order, and the last three numbers are1-7-8 in any order?

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  1. shivam_bhalla
    • 2 years ago
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    I think it is 3!

  2. jim_thompson5910
    • 2 years ago
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    There are 7 digits total. The first 4 are locked in at 202-1 So there are 7-4 = 3 digits left The last three numbers are 1-7-8 in any order and there are 3! = 3*2*1 = 6 ways to order them So there are 1*6 = 6 different phone numbers.

  3. lilai3
    • 2 years ago
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    Also for this question: Juan and Andrew are planning the schedule for a softball tournament. If there are 6 teams, how many different pairings could they make for the first tournament game? Is the answer to this one^^^^^ 6! which is 720 different pairings????? thank you got ur help!

  4. shivam_bhalla
    • 2 years ago
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    SimplyC(6,2)

  5. jim_thompson5910
    • 2 years ago
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    There are 6 teams to choose for the first slot (say the "home" slot) and 6-1 = 5 teams to choose for the second ("away/visitor") slot So there are 6*5 = 30 different ways to do this.

  6. lilai3
    • 2 years ago
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    oh so it's 30 instead for the answer to question number 2?

  7. jim_thompson5910
    • 2 years ago
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    If it's all being played on one field, then order doesn't matter, so you would divide by 2 to avoid the double counting.

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