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ERoseM

  • 3 years ago

Find the exact area (using the limit definition) between the curve f(x)=x^2+x+1, the x-axis and the vertical lines: x=-2 and x=3

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  1. saifoo.khan
    • 3 years ago
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    Integrate using limits..

  2. anonymous
    • 3 years ago
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    using a riemann sum? have fun

  3. saifoo.khan
    • 3 years ago
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    @satellite73 , Saw the Lunar Eclipse?

  4. anonymous
    • 3 years ago
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    no when was it?

  5. ERoseM
    • 3 years ago
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    Do I have to use the Riemann sum? that what I was questioning....

  6. saifoo.khan
    • 3 years ago
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    NOW! lol.

  7. saifoo.khan
    • 3 years ago
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    @satellite73 http://pinterest.com/slooh/slooh-space-camera-snaps/ Live photos.

  8. saifoo.khan
    • 3 years ago
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    @ERoseM use that integrating thing.

  9. anonymous
    • 3 years ago
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    damn it is cloudy and i am east coast

  10. saifoo.khan
    • 3 years ago
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    @satellite73 ; http://knue.com/solar-eclipse-this-sunday/ Georgia people can see too. If you want to see it live i can give u the link! ;D

  11. anonymous
    • 3 years ago
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    sure

  12. saifoo.khan
    • 3 years ago
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    \[\Large \int\limits_{-2}^{3} x^2 + x +1 .dx\] @ERoseM

  13. ERoseM
    • 3 years ago
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    I'm still confused, can anyone else explain it?

  14. saifoo.khan
    • 3 years ago
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    Confused? where?

  15. dpaInc
    • 3 years ago
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    you want to take the limit as n --> inf of the Riemann sum?

  16. saifoo.khan
    • 3 years ago
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    Why are you guys using Riemann?

  17. dpaInc
    • 3 years ago
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    because he said he wanted to get the area using the limit definition.... :)

  18. saifoo.khan
    • 3 years ago
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    umm.. so isn't limit thingy 3 and -2? i never studied this Riemann thingy! :D

  19. dpaInc
    • 3 years ago
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    niether have I.... !!!

  20. dpaInc
    • 3 years ago
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    kidding....

  21. saifoo.khan
    • 3 years ago
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    lol, i got confused for a sec.

  22. dpaInc
    • 3 years ago
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    Asker? is that what u wanted? limit definition?

  23. ERoseM
    • 3 years ago
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    Yes, thank you.

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