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- S

After an advertising campaign, the sales of a product often increase and then decrease. Suppose that t days after the end of the advertising the daily sales are,
f(t) = - 6t^2 + 64t + 105 units.
a) What is the average rate of growth in sales during the fourth day that is from time t = 3 to t = 4.
b) In what instantaneous rate are the sales changing when t=3?

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Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
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- S

- schrodinger

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- S

For a do you take a derivative and then plug in 3 and 4 and find the difference or what ?

- anonymous

a) Avg = [ f (4) - f(3) ] / ( 4 -3)
= f (4) - f(3)

- S

MMmm ok.. so just a difference with no derivative. Ok thanks!
What about b?

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- anonymous

b) instant rate = f' (3)

- S

Ok got it! Thank you!

- anonymous

Thanks for helping me to make it so simple ;)

- S

No problem.. hehe =D

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