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yes the question modified....

guys i need help @experimentX @Vincent-Lyon.Fr

Are you sure the 30° angle is with the floor and not with the wall?

the 30degrees is with the floor

Ok, now, have you tried applying the method I described earlier?

Do you know how to express the moment (torque) of a force about a certain point?

yep i do but get confused with the center of gravity constraint

What do you mean "constraint"?

the fact that the center of gravity of the ladder is one third the way up from the bottom.

|dw:1340887287738:dw| 30cos50 X 150 = R X bc

Here is the answer to your problem (see attached file):