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GS??

Geometric sequence :D

how that c-d is geometric mean of preceding and suceeding term

show that (c-d)^2 = b * (d-c)

these sequences are *

do this first ...
then use induction!!

ok ,what about the next require ? i dont even understand what he want !_!

looks like something went wrong ... verify that these are in Geometric progression first

if you use this, then you should be able to do the question.

Oh .. yes that's why i was getting this
http://www.wolframalpha.com/input/?i=255*55+%3D+155^2

yea thats right @asnaseer ,
anyways tysmm of your effort @experimentX

note the 2nd term should be "c-b" not "c-d"

otherwise 3rd term = -(2nd term)

which doesn't seem to make sense

do you agree Eyad?

must be a misprint

you should be able to use the formula I gave you to prove this fairly easily

maybe ....

I can do the first step for you if you want?

I am 100% sure its a misprint - and it is no bother at all to help you - always a pleasure :)

tysm @asnaseer ,ty too @experimentX ^_^ You guys rocks

yea...

yes ,that right i have just proved it ..continue Please

sorry that should be - similarly, you should be able to show:\[d-c=br^{2n}\]

so you will be left with the sequence:\[b,c-b,d-c,...\]which equals:\[b,br^n,br^{2n},...\]

which is a geometric sequence

aha ,now i will be able to prove it can be added to infinite G.s

yes

ty ,ima be sure of the 2nd require and then call you back :DDD

ok - good luck! :)