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octoberchick1011 Group Title

An equilateral triangle with sides of length 6 is inscribed in a circle. What is the diameter of the circle?

  • 2 years ago
  • 2 years ago

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  1. dpaInc Group Title
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    |dw:1337641995914:dw| because your dealing with a 30-60-90 triangle, you can solve that triangle for r: 3^2 = (3/2)^2 + r^2 solve for r, your radius.

    • 2 years ago
  2. octoberchick1011 Group Title
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    Okay! Thank you! :)

    • 2 years ago
  3. dpaInc Group Title
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    yw... you want an answer verification?

    • 2 years ago
  4. octoberchick1011 Group Title
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    Yes please!

    • 2 years ago
  5. dpaInc Group Title
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    ok.. tell me what u got an i'll tell you mine...

    • 2 years ago
  6. octoberchick1011 Group Title
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    Well, for the answer to the question, I got 6.9.. Is that right?

    • 2 years ago
  7. dpaInc Group Title
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    i got 3(sqrt3)/2 or about 2.6

    • 2 years ago
  8. dpaInc Group Title
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    hmm... wanna go over the work?

    • 2 years ago
  9. asnaseer Group Title
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    6.9 is the correct answer for the diameter

    • 2 years ago
  10. dpaInc Group Title
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    ohh... hahah... thanks @asnaseer ..

    • 2 years ago
  11. asnaseer Group Title
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    yw :)

    • 2 years ago
  12. dpaInc Group Title
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    sorry, I meant @octoberchick , your correct... :)

    • 2 years ago
  13. asnaseer Group Title
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    btw: I did it in a slightly different way: |dw:1337643034380:dw| bisect one of the angles of the equilateral triangle to get...

    • 2 years ago
  14. asnaseer Group Title
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    |dw:1337643091539:dw|

    • 2 years ago
  15. asnaseer Group Title
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    then, in the right angled triangle ABC:\[\cos(30)=6/d\]therefore:\[d=6/\cos(30)\]

    • 2 years ago
  16. dpaInc Group Title
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    wow.... isn't it great having to see other methods? and this is still a 30-60-90 triangle so trig functions aren't really needed still. thanks... :)

    • 2 years ago
  17. asnaseer Group Title
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    true... :)

    • 2 years ago
  18. dpaInc Group Title
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    and i think that is a lot more clear ^^^... :)

    • 2 years ago
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