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 2 years ago
An equilateral triangle with sides of length 6 is inscribed in a circle. What is the diameter of the circle?
 2 years ago
An equilateral triangle with sides of length 6 is inscribed in a circle. What is the diameter of the circle?

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dpaInc
 2 years ago
Best ResponseYou've already chosen the best response.2dw:1337641995914:dw because your dealing with a 306090 triangle, you can solve that triangle for r: 3^2 = (3/2)^2 + r^2 solve for r, your radius.

octoberchick1011
 2 years ago
Best ResponseYou've already chosen the best response.0Okay! Thank you! :)

dpaInc
 2 years ago
Best ResponseYou've already chosen the best response.2yw... you want an answer verification?

dpaInc
 2 years ago
Best ResponseYou've already chosen the best response.2ok.. tell me what u got an i'll tell you mine...

octoberchick1011
 2 years ago
Best ResponseYou've already chosen the best response.0Well, for the answer to the question, I got 6.9.. Is that right?

dpaInc
 2 years ago
Best ResponseYou've already chosen the best response.2i got 3(sqrt3)/2 or about 2.6

dpaInc
 2 years ago
Best ResponseYou've already chosen the best response.2hmm... wanna go over the work?

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.26.9 is the correct answer for the diameter

dpaInc
 2 years ago
Best ResponseYou've already chosen the best response.2ohh... hahah... thanks @asnaseer ..

dpaInc
 2 years ago
Best ResponseYou've already chosen the best response.2sorry, I meant @octoberchick , your correct... :)

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.2btw: I did it in a slightly different way: dw:1337643034380:dw bisect one of the angles of the equilateral triangle to get...

asnaseer
 2 years ago
Best ResponseYou've already chosen the best response.2then, in the right angled triangle ABC:\[\cos(30)=6/d\]therefore:\[d=6/\cos(30)\]

dpaInc
 2 years ago
Best ResponseYou've already chosen the best response.2wow.... isn't it great having to see other methods? and this is still a 306090 triangle so trig functions aren't really needed still. thanks... :)

dpaInc
 2 years ago
Best ResponseYou've already chosen the best response.2and i think that is a lot more clear ^^^... :)
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