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octoberchick1011

  • 3 years ago

An equilateral triangle with sides of length 6 is inscribed in a circle. What is the diameter of the circle?

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  1. dpaInc
    • 3 years ago
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    |dw:1337641995914:dw| because your dealing with a 30-60-90 triangle, you can solve that triangle for r: 3^2 = (3/2)^2 + r^2 solve for r, your radius.

  2. octoberchick1011
    • 3 years ago
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    Okay! Thank you! :)

  3. dpaInc
    • 3 years ago
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    yw... you want an answer verification?

  4. octoberchick1011
    • 3 years ago
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    Yes please!

  5. dpaInc
    • 3 years ago
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    ok.. tell me what u got an i'll tell you mine...

  6. octoberchick1011
    • 3 years ago
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    Well, for the answer to the question, I got 6.9.. Is that right?

  7. dpaInc
    • 3 years ago
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    i got 3(sqrt3)/2 or about 2.6

  8. dpaInc
    • 3 years ago
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    hmm... wanna go over the work?

  9. asnaseer
    • 3 years ago
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    6.9 is the correct answer for the diameter

  10. dpaInc
    • 3 years ago
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    ohh... hahah... thanks @asnaseer ..

  11. asnaseer
    • 3 years ago
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    yw :)

  12. dpaInc
    • 3 years ago
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    sorry, I meant @octoberchick , your correct... :)

  13. asnaseer
    • 3 years ago
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    btw: I did it in a slightly different way: |dw:1337643034380:dw| bisect one of the angles of the equilateral triangle to get...

  14. asnaseer
    • 3 years ago
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    |dw:1337643091539:dw|

  15. asnaseer
    • 3 years ago
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    then, in the right angled triangle ABC:\[\cos(30)=6/d\]therefore:\[d=6/\cos(30)\]

  16. dpaInc
    • 3 years ago
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    wow.... isn't it great having to see other methods? and this is still a 30-60-90 triangle so trig functions aren't really needed still. thanks... :)

  17. asnaseer
    • 3 years ago
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    true... :)

  18. dpaInc
    • 3 years ago
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    and i think that is a lot more clear ^^^... :)

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