## octoberchick1011 Group Title An equilateral triangle with sides of length 6 is inscribed in a circle. What is the diameter of the circle? 2 years ago 2 years ago

1. dpaInc Group Title

|dw:1337641995914:dw| because your dealing with a 30-60-90 triangle, you can solve that triangle for r: 3^2 = (3/2)^2 + r^2 solve for r, your radius.

2. octoberchick1011 Group Title

Okay! Thank you! :)

3. dpaInc Group Title

yw... you want an answer verification?

4. octoberchick1011 Group Title

5. dpaInc Group Title

ok.. tell me what u got an i'll tell you mine...

6. octoberchick1011 Group Title

Well, for the answer to the question, I got 6.9.. Is that right?

7. dpaInc Group Title

i got 3(sqrt3)/2 or about 2.6

8. dpaInc Group Title

hmm... wanna go over the work?

9. asnaseer Group Title

6.9 is the correct answer for the diameter

10. dpaInc Group Title

ohh... hahah... thanks @asnaseer ..

11. asnaseer Group Title

yw :)

12. dpaInc Group Title

sorry, I meant @octoberchick , your correct... :)

13. asnaseer Group Title

btw: I did it in a slightly different way: |dw:1337643034380:dw| bisect one of the angles of the equilateral triangle to get...

14. asnaseer Group Title

|dw:1337643091539:dw|

15. asnaseer Group Title

then, in the right angled triangle ABC:$\cos(30)=6/d$therefore:$d=6/\cos(30)$

16. dpaInc Group Title

wow.... isn't it great having to see other methods? and this is still a 30-60-90 triangle so trig functions aren't really needed still. thanks... :)

17. asnaseer Group Title

true... :)

18. dpaInc Group Title

and i think that is a lot more clear ^^^... :)