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anonymous
 4 years ago
An equilateral triangle with sides of length 6 is inscribed in a circle. What is the diameter of the circle?
anonymous
 4 years ago
An equilateral triangle with sides of length 6 is inscribed in a circle. What is the diameter of the circle?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1337641995914:dw because your dealing with a 306090 triangle, you can solve that triangle for r: 3^2 = (3/2)^2 + r^2 solve for r, your radius.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yw... you want an answer verification?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok.. tell me what u got an i'll tell you mine...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well, for the answer to the question, I got 6.9.. Is that right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i got 3(sqrt3)/2 or about 2.6

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hmm... wanna go over the work?

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.36.9 is the correct answer for the diameter

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohh... hahah... thanks @asnaseer ..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry, I meant @octoberchick , your correct... :)

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.3btw: I did it in a slightly different way: dw:1337643034380:dw bisect one of the angles of the equilateral triangle to get...

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.3then, in the right angled triangle ABC:\[\cos(30)=6/d\]therefore:\[d=6/\cos(30)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wow.... isn't it great having to see other methods? and this is still a 306090 triangle so trig functions aren't really needed still. thanks... :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and i think that is a lot more clear ^^^... :)
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