## octoberchick1011 3 years ago An equilateral triangle with sides of length 6 is inscribed in a circle. What is the diameter of the circle?

1. dpaInc

|dw:1337641995914:dw| because your dealing with a 30-60-90 triangle, you can solve that triangle for r: 3^2 = (3/2)^2 + r^2 solve for r, your radius.

2. octoberchick1011

Okay! Thank you! :)

3. dpaInc

yw... you want an answer verification?

4. octoberchick1011

5. dpaInc

ok.. tell me what u got an i'll tell you mine...

6. octoberchick1011

Well, for the answer to the question, I got 6.9.. Is that right?

7. dpaInc

i got 3(sqrt3)/2 or about 2.6

8. dpaInc

hmm... wanna go over the work?

9. asnaseer

6.9 is the correct answer for the diameter

10. dpaInc

ohh... hahah... thanks @asnaseer ..

11. asnaseer

yw :)

12. dpaInc

sorry, I meant @octoberchick , your correct... :)

13. asnaseer

btw: I did it in a slightly different way: |dw:1337643034380:dw| bisect one of the angles of the equilateral triangle to get...

14. asnaseer

|dw:1337643091539:dw|

15. asnaseer

then, in the right angled triangle ABC:$\cos(30)=6/d$therefore:$d=6/\cos(30)$

16. dpaInc

wow.... isn't it great having to see other methods? and this is still a 30-60-90 triangle so trig functions aren't really needed still. thanks... :)

17. asnaseer

true... :)

18. dpaInc

and i think that is a lot more clear ^^^... :)