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Find the cosine of angle A. 0.88 BC=8 AB=17 AC=15

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in right angled triangle,,whats cos of an angle mam ?
cosA= base/hypotenuse = AC/AB

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Other answers:

(if it's a right angled triangle)
\(\ \Huge cos=\frac{adj}{hyp}=\frac{AC}{AB}=\frac{15}{17} \).
im asking if that the way you write these answer with a zero at first 0.88
tell me this,,which is greater ,, 0.88 , 00.88 , .88 ?
dont matter
huh ?
i mean they are the same
yes..exactly.. so it dosent matter if you write 0.88 or .88 or anything of that sort..
ok thx

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