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Ruchi. Group Title

the velocity v and displacement x of a particle executing simple harmonic motion are related as

  • 2 years ago
  • 2 years ago

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  1. Ruchi. Group Title
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    |dw:1337667924733:dw| at x=0,v=v0.finnd velocity v when the displacement becomes x.

    • 2 years ago
  2. apoorvk Group Title
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    That^ equation is incorrect. If you see carefully, it is not dimensionally correct.

    • 2 years ago
  3. stormfire1 Group Title
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    I was about to ask :)

    • 2 years ago
  4. Ruchi. Group Title
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    its correct

    • 2 years ago
  5. apoorvk Group Title
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    Should be I guess:|dw:1337668280053:dw|

    • 2 years ago
  6. apoorvk Group Title
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    check out the dimensions @Ruchi. , and compare to the prev. one.

    • 2 years ago
  7. Ruchi. Group Title
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    yes ur right.

    • 2 years ago
  8. apoorvk Group Title
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    So, where's the trouble lie?

    • 2 years ago
  9. apoorvk Group Title
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    Problem kahaan hai??

    • 2 years ago
  10. Vincent-Lyon.Fr Group Title
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    It should read: \(\Large \frac {dv}{dt}\normalsize =-\omega_0^2x \)

    • 2 years ago
  11. apoorvk Group Title
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    dv/dt = vdv/dx = a

    • 2 years ago
  12. apoorvk Group Title
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    right?

    • 2 years ago
  13. Ruchi. Group Title
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    yes

    • 2 years ago
  14. Aadarsh Group Title
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    yes

    • 2 years ago
  15. apoorvk Group Title
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    so, wherein does the trouble lie??

    • 2 years ago
  16. Disintegrati Group Title
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    |dw:1337670911339:dw|

    • 2 years ago
  17. binary3i Group Title
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    \[v = \omega \sqrt{A^2 - x^2} \] where a is the amplitude

    • 2 years ago
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