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Ruchi.

  • 3 years ago

the velocity v and displacement x of a particle executing simple harmonic motion are related as

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  1. Ruchi.
    • 3 years ago
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    |dw:1337667924733:dw| at x=0,v=v0.finnd velocity v when the displacement becomes x.

  2. apoorvk
    • 3 years ago
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    That^ equation is incorrect. If you see carefully, it is not dimensionally correct.

  3. stormfire1
    • 3 years ago
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    I was about to ask :)

  4. Ruchi.
    • 3 years ago
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    its correct

  5. apoorvk
    • 3 years ago
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    Should be I guess:|dw:1337668280053:dw|

  6. apoorvk
    • 3 years ago
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    check out the dimensions @Ruchi. , and compare to the prev. one.

  7. Ruchi.
    • 3 years ago
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    yes ur right.

  8. apoorvk
    • 3 years ago
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    So, where's the trouble lie?

  9. apoorvk
    • 3 years ago
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    Problem kahaan hai??

  10. Vincent-Lyon.Fr
    • 3 years ago
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    It should read: \(\Large \frac {dv}{dt}\normalsize =-\omega_0^2x \)

  11. apoorvk
    • 3 years ago
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    dv/dt = vdv/dx = a

  12. apoorvk
    • 3 years ago
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    right?

  13. Ruchi.
    • 3 years ago
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    yes

  14. Aadarsh
    • 3 years ago
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    yes

  15. apoorvk
    • 3 years ago
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    so, wherein does the trouble lie??

  16. Disintegrati
    • 3 years ago
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    |dw:1337670911339:dw|

  17. binary3i
    • 3 years ago
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    \[v = \omega \sqrt{A^2 - x^2} \] where a is the amplitude

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