anonymous
  • anonymous
the velocity v and displacement x of a particle executing simple harmonic motion are related as
Physics
chestercat
  • chestercat
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
|dw:1337667924733:dw| at x=0,v=v0.finnd velocity v when the displacement becomes x.
apoorvk
  • apoorvk
That^ equation is incorrect. If you see carefully, it is not dimensionally correct.
stormfire1
  • stormfire1
I was about to ask :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
its correct
apoorvk
  • apoorvk
Should be I guess:|dw:1337668280053:dw|
apoorvk
  • apoorvk
check out the dimensions @Ruchi. , and compare to the prev. one.
anonymous
  • anonymous
yes ur right.
apoorvk
  • apoorvk
So, where's the trouble lie?
apoorvk
  • apoorvk
Problem kahaan hai??
Vincent-Lyon.Fr
  • Vincent-Lyon.Fr
It should read: \(\Large \frac {dv}{dt}\normalsize =-\omega_0^2x \)
apoorvk
  • apoorvk
dv/dt = vdv/dx = a
apoorvk
  • apoorvk
right?
anonymous
  • anonymous
yes
anonymous
  • anonymous
yes
apoorvk
  • apoorvk
so, wherein does the trouble lie??
anonymous
  • anonymous
|dw:1337670911339:dw|
binary3i
  • binary3i
\[v = \omega \sqrt{A^2 - x^2} \] where a is the amplitude

Looking for something else?

Not the answer you are looking for? Search for more explanations.