Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

eliassaabBest ResponseYou've already chosen the best response.2
\[ \frac{x1}{x^2 \left(x^2+1\right)}=\frac{A}{x^2}+\frac{B}{x}+\frac{C x+D}{x^2+1} \]
 one year ago

nbouscalBest ResponseYou've already chosen the best response.0
\[ A(x^2+1)+Bx(x^2+1)+(Cx+D)x^2=x1 \]
 one year ago

eliassaabBest ResponseYou've already chosen the best response.2
Multiply bith sides by x^2 and make x =0, you get A= 1
 one year ago

nbouscalBest ResponseYou've already chosen the best response.0
Do you know how to take it from there, @Silenthill ?
 one year ago

eliassaabBest ResponseYou've already chosen the best response.2
\[ \frac{x1}{x^2 \left(x^2+1\right)}=\frac{A}{x^2}+\frac{B}{x}+\frac{C x+D}{x^2+1} \] Multilpy both sides by x^2 + 1 and make x = i\[ \frac {i1} {1} = Ci + D= i+1\\ C=1\\ D=1\\ \]
 one year ago

eliassaabBest ResponseYou've already chosen the best response.2
\[ \frac{x1}{x^2 \left(x^2+1\right)}=\frac{A}{x^2}+\frac{B}{x}+\frac{C x+D}{x^2+1} \] Multiply both sides by x and let x goes to Infinity, you get 0 = B + C B=C=1 Putting everything together, you get \[ \frac{x1}{x^2 \left(x^2+1\right)}=\frac{1x}{x^2+1}\frac{1}{x^2}+\frac{1}{x} \]
 one year ago

matrickedBest ResponseYou've already chosen the best response.0
given question equals x/(x^2(x^2+1) 1/(x^2(x^2+1) first part can be done usin u=x^2 and then applying partial factor method whereas the second part can be seperated as1/(x^2)1/(x^2+1) and then both the parts can be integrated easily
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.