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How do you find perimeter of square if given the diagonal?

Mathematics
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Hey :)
After solving.
It just involves pythagorean theorem.

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Other answers:

|dw:1337701107499:dw|
|dw:1337701083545:dw| Here it is. Just put in the formula: c^2 = 2a^2(a = b)(diagonal = c
5 is the value i just supposed?
It is 5, & I got 3.5, but it's wrong x_x
d^2=2*s^2
solve for s
?!!? baaah |dw:1337701419454:dw|
Perimeter= 2x sqr rt2 x diagonal D
Am i correct?
d^2=2*s^2 Solve for s then it is s*4
\[d^2=s^2+s^2\] \[d^2=2s^2\] \[(d^2)/2=s^2\] \[s=d/\sqrt{2} \] P=4*s \[s=4*d/\sqrt{2} \] \[s=2\sqrt{2}*d \]
last to s's should be P's
1) divide by \(\sqrt{2}\) to get the length of the side then 2) multiply by 4 to get the length of the perimeter
I got itttt. Thaanks errybody!

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