kymber
How do you find perimeter of square if given the diagonal?



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ParthKohli
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Hey :)

saifoo.khan
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After solving.

ParthKohli
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It just involves pythagorean theorem.

saifoo.khan
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dw:1337701107499:dw

ParthKohli
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dw:1337701083545:dw
Here it is. Just put in the formula:
c^2 = 2a^2(a = b)(diagonal = c

saifoo.khan
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5 is the value i just supposed?

kymber
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It is 5, & I got 3.5, but it's wrong x_x

timo86m
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d^2=2*s^2

timo86m
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solve for s

kymber
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?!!? baaah
dw:1337701419454:dw

SMISHRA
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Perimeter= 2x sqr rt2 x diagonal D

SMISHRA
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Am i correct?

timo86m
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d^2=2*s^2
Solve for s
then it is s*4

Mathmuse
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\[d^2=s^2+s^2\]
\[d^2=2s^2\]
\[(d^2)/2=s^2\]
\[s=d/\sqrt{2} \]
P=4*s
\[s=4*d/\sqrt{2} \]
\[s=2\sqrt{2}*d \]

Mathmuse
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last to s's should be P's

anonymous
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1) divide by \(\sqrt{2}\) to get the length of the side then
2) multiply by 4 to get the length of the perimeter

kymber
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I got itttt. Thaanks errybody!