A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.2It just involves pythagorean theorem.

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1337701107499:dw

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.2dw:1337701083545:dw Here it is. Just put in the formula: c^2 = 2a^2(a = b)(diagonal = c

saifoo.khan
 2 years ago
Best ResponseYou've already chosen the best response.15 is the value i just supposed?

kymber
 2 years ago
Best ResponseYou've already chosen the best response.4It is 5, & I got 3.5, but it's wrong x_x

kymber
 2 years ago
Best ResponseYou've already chosen the best response.4?!!? baaah dw:1337701419454:dw

SMISHRA
 2 years ago
Best ResponseYou've already chosen the best response.0Perimeter= 2x sqr rt2 x diagonal D

timo86m
 2 years ago
Best ResponseYou've already chosen the best response.0d^2=2*s^2 Solve for s then it is s*4

Mathmuse
 2 years ago
Best ResponseYou've already chosen the best response.0\[d^2=s^2+s^2\] \[d^2=2s^2\] \[(d^2)/2=s^2\] \[s=d/\sqrt{2} \] P=4*s \[s=4*d/\sqrt{2} \] \[s=2\sqrt{2}*d \]

Mathmuse
 2 years ago
Best ResponseYou've already chosen the best response.0last to s's should be P's

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.01) divide by \(\sqrt{2}\) to get the length of the side then 2) multiply by 4 to get the length of the perimeter

kymber
 2 years ago
Best ResponseYou've already chosen the best response.4I got itttt. Thaanks errybody!
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.