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kymber

How do you find perimeter of square if given the diagonal?

  • one year ago
  • one year ago

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  1. ParthKohli
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    Hey :)

    • one year ago
  2. saifoo.khan
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    After solving.

    • one year ago
  3. ParthKohli
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    It just involves pythagorean theorem.

    • one year ago
  4. saifoo.khan
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    |dw:1337701107499:dw|

    • one year ago
  5. ParthKohli
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    |dw:1337701083545:dw| Here it is. Just put in the formula: c^2 = 2a^2(a = b)(diagonal = c

    • one year ago
  6. saifoo.khan
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    5 is the value i just supposed?

    • one year ago
  7. kymber
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    It is 5, & I got 3.5, but it's wrong x_x

    • one year ago
  8. timo86m
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    d^2=2*s^2

    • one year ago
  9. timo86m
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    solve for s

    • one year ago
  10. kymber
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    ?!!? baaah |dw:1337701419454:dw|

    • one year ago
  11. SMISHRA
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    Perimeter= 2x sqr rt2 x diagonal D

    • one year ago
  12. SMISHRA
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    Am i correct?

    • one year ago
  13. timo86m
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    d^2=2*s^2 Solve for s then it is s*4

    • one year ago
  14. Mathmuse
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    \[d^2=s^2+s^2\] \[d^2=2s^2\] \[(d^2)/2=s^2\] \[s=d/\sqrt{2} \] P=4*s \[s=4*d/\sqrt{2} \] \[s=2\sqrt{2}*d \]

    • one year ago
  15. Mathmuse
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    last to s's should be P's

    • one year ago
  16. satellite73
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    1) divide by \(\sqrt{2}\) to get the length of the side then 2) multiply by 4 to get the length of the perimeter

    • one year ago
  17. kymber
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    I got itttt. Thaanks errybody!

    • one year ago
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