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- kymber

I don't understand how to do problems like these :'(

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- kymber

I don't understand how to do problems like these :'(

- schrodinger

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- kymber

- anonymous

bears...or 42 im unsure which

- kymber

BLEEEEEEEEH

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- anonymous

not helping?

- experimentX

\[ \sin 50 = 100/x\]
find x using calculator

- kymber

Can you explain, though!!?

- experimentX

\[ \sin \theta = p/h\]
the question is asking you to find h ... and also note this is a right angled triangle

- anonymous

trig ratios is what you need to know for these

- anonymous

btw it is not sine in this case but tangent i think

- kymber

I know the trig ratios, SOH CAH TOA

- anonymous

oh no, it is sine my fault!!

- anonymous

should have known better.
do you know the trig ratios for a triangle?

- kymber

Is it not SOH CAH TOA?!?!!?!

- anonymous

|dw:1337707416006:dw|

- anonymous

so for the angle given , lets call it \(x\) in terms of \(a, b, c\) can you say what
\[\sin(x)\] is?
you are right, you can use soh cah toa if you know what they mean

- anonymous

so in your picture, you are trying to find the hypotenuse \(h\) so you know from "SOH" that the sine of 50 is the opposite over the hypotenuse, or
\[\sin(50)=\frac{100}{h}\] and then you solve for \(h\) via
\[h=\frac{100}{\sin(50)}\]

- anonymous

got that or still confusing?

- kymber

Uuh, I think I got itt, thanks a bunch for helping meee! :D

- anonymous

yw
we can try another if you like

- kymber

That's okaay, I'm prettyy sure I got it! c;

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