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kymber

  • 3 years ago

I don't understand how to do problems like these :'(

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  1. kymber
    • 3 years ago
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  2. jasonsmart
    • 3 years ago
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    bears...or 42 im unsure which

  3. kymber
    • 3 years ago
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    BLEEEEEEEEH

  4. jasonsmart
    • 3 years ago
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    not helping?

  5. experimentX
    • 3 years ago
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    \[ \sin 50 = 100/x\] find x using calculator

  6. kymber
    • 3 years ago
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    Can you explain, though!!?

  7. experimentX
    • 3 years ago
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    \[ \sin \theta = p/h\] the question is asking you to find h ... and also note this is a right angled triangle

  8. anonymous
    • 3 years ago
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    trig ratios is what you need to know for these

  9. anonymous
    • 3 years ago
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    btw it is not sine in this case but tangent i think

  10. kymber
    • 3 years ago
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    I know the trig ratios, SOH CAH TOA

  11. anonymous
    • 3 years ago
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    oh no, it is sine my fault!!

  12. anonymous
    • 3 years ago
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    should have known better. do you know the trig ratios for a triangle?

  13. kymber
    • 3 years ago
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    Is it not SOH CAH TOA?!?!!?!

  14. anonymous
    • 3 years ago
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    |dw:1337707416006:dw|

  15. anonymous
    • 3 years ago
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    so for the angle given , lets call it \(x\) in terms of \(a, b, c\) can you say what \[\sin(x)\] is? you are right, you can use soh cah toa if you know what they mean

  16. anonymous
    • 3 years ago
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    so in your picture, you are trying to find the hypotenuse \(h\) so you know from "SOH" that the sine of 50 is the opposite over the hypotenuse, or \[\sin(50)=\frac{100}{h}\] and then you solve for \(h\) via \[h=\frac{100}{\sin(50)}\]

  17. anonymous
    • 3 years ago
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    got that or still confusing?

  18. kymber
    • 3 years ago
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    Uuh, I think I got itt, thanks a bunch for helping meee! :D

  19. anonymous
    • 3 years ago
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    yw we can try another if you like

  20. kymber
    • 3 years ago
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    That's okaay, I'm prettyy sure I got it! c;

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