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jasonsmart Group TitleBest ResponseYou've already chosen the best response.0
bears...or 42 im unsure which
 2 years ago

jasonsmart Group TitleBest ResponseYou've already chosen the best response.0
not helping?
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
\[ \sin 50 = 100/x\] find x using calculator
 2 years ago

kymber Group TitleBest ResponseYou've already chosen the best response.4
Can you explain, though!!?
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
\[ \sin \theta = p/h\] the question is asking you to find h ... and also note this is a right angled triangle
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
trig ratios is what you need to know for these
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
btw it is not sine in this case but tangent i think
 2 years ago

kymber Group TitleBest ResponseYou've already chosen the best response.4
I know the trig ratios, SOH CAH TOA
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
oh no, it is sine my fault!!
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
should have known better. do you know the trig ratios for a triangle?
 2 years ago

kymber Group TitleBest ResponseYou've already chosen the best response.4
Is it not SOH CAH TOA?!?!!?!
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
dw:1337707416006:dw
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
so for the angle given , lets call it \(x\) in terms of \(a, b, c\) can you say what \[\sin(x)\] is? you are right, you can use soh cah toa if you know what they mean
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
so in your picture, you are trying to find the hypotenuse \(h\) so you know from "SOH" that the sine of 50 is the opposite over the hypotenuse, or \[\sin(50)=\frac{100}{h}\] and then you solve for \(h\) via \[h=\frac{100}{\sin(50)}\]
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
got that or still confusing?
 2 years ago

kymber Group TitleBest ResponseYou've already chosen the best response.4
Uuh, I think I got itt, thanks a bunch for helping meee! :D
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
yw we can try another if you like
 2 years ago

kymber Group TitleBest ResponseYou've already chosen the best response.4
That's okaay, I'm prettyy sure I got it! c;
 2 years ago
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