kymber
  • kymber
I don't understand how to do problems like these :'(
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
kymber
  • kymber
1 Attachment
anonymous
  • anonymous
bears...or 42 im unsure which
kymber
  • kymber
BLEEEEEEEEH

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anonymous
  • anonymous
not helping?
experimentX
  • experimentX
\[ \sin 50 = 100/x\] find x using calculator
kymber
  • kymber
Can you explain, though!!?
experimentX
  • experimentX
\[ \sin \theta = p/h\] the question is asking you to find h ... and also note this is a right angled triangle
anonymous
  • anonymous
trig ratios is what you need to know for these
anonymous
  • anonymous
btw it is not sine in this case but tangent i think
kymber
  • kymber
I know the trig ratios, SOH CAH TOA
anonymous
  • anonymous
oh no, it is sine my fault!!
anonymous
  • anonymous
should have known better. do you know the trig ratios for a triangle?
kymber
  • kymber
Is it not SOH CAH TOA?!?!!?!
anonymous
  • anonymous
|dw:1337707416006:dw|
anonymous
  • anonymous
so for the angle given , lets call it \(x\) in terms of \(a, b, c\) can you say what \[\sin(x)\] is? you are right, you can use soh cah toa if you know what they mean
anonymous
  • anonymous
so in your picture, you are trying to find the hypotenuse \(h\) so you know from "SOH" that the sine of 50 is the opposite over the hypotenuse, or \[\sin(50)=\frac{100}{h}\] and then you solve for \(h\) via \[h=\frac{100}{\sin(50)}\]
anonymous
  • anonymous
got that or still confusing?
kymber
  • kymber
Uuh, I think I got itt, thanks a bunch for helping meee! :D
anonymous
  • anonymous
yw we can try another if you like
kymber
  • kymber
That's okaay, I'm prettyy sure I got it! c;

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