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kymber
 4 years ago
I don't understand how to do problems like these :'(
kymber
 4 years ago
I don't understand how to do problems like these :'(

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0bears...or 42 im unsure which

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.0\[ \sin 50 = 100/x\] find x using calculator

kymber
 4 years ago
Best ResponseYou've already chosen the best response.4Can you explain, though!!?

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.0\[ \sin \theta = p/h\] the question is asking you to find h ... and also note this is a right angled triangle

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0trig ratios is what you need to know for these

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0btw it is not sine in this case but tangent i think

kymber
 4 years ago
Best ResponseYou've already chosen the best response.4I know the trig ratios, SOH CAH TOA

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh no, it is sine my fault!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0should have known better. do you know the trig ratios for a triangle?

kymber
 4 years ago
Best ResponseYou've already chosen the best response.4Is it not SOH CAH TOA?!?!!?!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1337707416006:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so for the angle given , lets call it \(x\) in terms of \(a, b, c\) can you say what \[\sin(x)\] is? you are right, you can use soh cah toa if you know what they mean

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so in your picture, you are trying to find the hypotenuse \(h\) so you know from "SOH" that the sine of 50 is the opposite over the hypotenuse, or \[\sin(50)=\frac{100}{h}\] and then you solve for \(h\) via \[h=\frac{100}{\sin(50)}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0got that or still confusing?

kymber
 4 years ago
Best ResponseYou've already chosen the best response.4Uuh, I think I got itt, thanks a bunch for helping meee! :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yw we can try another if you like

kymber
 4 years ago
Best ResponseYou've already chosen the best response.4That's okaay, I'm prettyy sure I got it! c;
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