1. Mathhelp346

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2. rebecca1233

Thanks. do you know how to do this

3. Mathhelp346

all you would need to do is come up with 2 binomials and then distribute to get the answer

4. Mathhelp346

so if i gave you (a+b)(a+b), the answer would be a^2+ab+ba+b^2, or a^2+2ab+b^2

5. Mathhelp346

ok, give me 2 numbers

6. rebecca1233

can you give me one please cause im quite confused so like x^2 -a -25 ?

7. Mathhelp346

um not exactly

8. rebecca1233

can i use yours as one? cause im quite confused lol

9. Mathhelp346

so let's say you have (2+3)(4+5)

10. Mathhelp346

11. Mathhelp346

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12. rebecca1233

uhmm

13. Mathhelp346

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14. rebecca1233

times? 2 * 4 = 8

15. Mathhelp346

yes

16. rebecca1233

& 3 *5 = 15

17. Mathhelp346

yes, and...?

18. rebecca1233

so what would the end look like ?

19. rebecca1233

(8+5) ?

20. rebecca1233

(8+15)

21. Mathhelp346

Rebecca, there's still more. You need to distribute the 2 to both the 4 and 5. Same goes for the 3.

22. rebecca1233

im so confused can you show me ?

23. Mathhelp346

So basically, you would be solving 2*4+2*5+3*4+3*5

24. Mathhelp346

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25. rebecca1233

simplifying?

26. Mathhelp346

actually, we need some x's. hold on.

27. rebecca1233

28. Mathhelp346

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29. Mathhelp346

here

30. rebecca1233

Thank you.. i got it :)

31. Mathhelp346

ok

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