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Ruchi.

  • 3 years ago

A compound of vanadium has a magnetic moment of 1.73 BM.WORK out the electronic configuration of the vanadium ion in the compound.

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  1. shivam_bhalla
    • 3 years ago
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    \[Magnetic \space moment = \sqrt{n(n+2)}\] where n-->number of unpaired electron :)

  2. Ruchi.
    • 3 years ago
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    n=3

  3. Ruchi.
    • 3 years ago
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    its given that u=1.73

  4. Ruchi.
    • 3 years ago
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    i m confuse

  5. shivam_bhalla
    • 3 years ago
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    @Ruchi. \[1.73 = \sqrt{n(n+2)}\] Therefore n = 1 Therefore number of unpaired electron = 1 Now try to finish it off :)

  6. Ruchi.
    • 3 years ago
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    its answer=[Ar]3d1

  7. Ruchi.
    • 3 years ago
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    hw u gt n=1

  8. shivam_bhalla
    • 3 years ago
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    @Ruchi. , substitute n=1 and see in the formula :P

  9. Ruchi.
    • 3 years ago
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    wait

  10. Ruchi.
    • 3 years ago
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    1.73 = sqrt(3) = sqrt(n(n+2)) So, n(n+2) = 3 or n = 1 For V, Z = 23, [Ar]4s23d3 am i right.

  11. shivam_bhalla
    • 3 years ago
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    Yes. @Ruchi, now tell me if Vanadium has 3 unpaired electrons, and you know that the vanadium ion is having 1 unpaired electron, then now can you figure out the charge on vanadium ion :)

  12. Ruchi.
    • 3 years ago
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    @shivam_bhalla i m nt getting its electrnic configration

  13. Ruchi.
    • 3 years ago
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    1s2 2s2 2p6 3s2 3p6 4s2 3d3.

  14. shivam_bhalla
    • 3 years ago
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    @Ruchi. , This question is more intersesting now :P. Let me have a check and let you know the electron configuration.

  15. shivam_bhalla
    • 3 years ago
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    @Ruchi. Your task is to get a vanadium ion with 1 unpaired electron . Now a simple question to you , first where will you remove the electron from vanadium first ?? s orbital or p orbital ?

  16. Ruchi.
    • 3 years ago
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    p

  17. shivam_bhalla
    • 3 years ago
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    Typo ; I meant 3s orbital or 3d orbital ??

  18. Ruchi.
    • 3 years ago
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    V+4=1S2 2s2 2p6 3s2 3p6 3d1.

  19. Ruchi.
    • 3 years ago
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    am i right.

  20. Ruchi.
    • 3 years ago
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    what r u telling i m nt understanding.

  21. shivam_bhalla
    • 3 years ago
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    Ruchi, The configuration you gave for V4+ is wrong. Think why ?? (tip:check the number of electrons is 4s orbital )

  22. shivam_bhalla
    • 3 years ago
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    You should always mention 4s 0 while writing the V4+ configuration. So you are partially right @Ruchi.

  23. shivam_bhalla
    • 3 years ago
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    @Ruchi. V+4=1S2 2s2 2p6 3s2 3p6 4s0 3d1

  24. Ruchi.
    • 3 years ago
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    0 ka mention torina nakariga.

  25. Ruchi.
    • 3 years ago
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    kariga

  26. shivam_bhalla
    • 3 years ago
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    Revise aufbau principle @ruchi. Remove 2 electrons from 4s orbital, then 2 electrons from 3d orbital to get V4+

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