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Ruchi. Group Title

A compound of vanadium has a magnetic moment of 1.73 BM.WORK out the electronic configuration of the vanadium ion in the compound.

  • 2 years ago
  • 2 years ago

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  1. shivam_bhalla Group Title
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    \[Magnetic \space moment = \sqrt{n(n+2)}\] where n-->number of unpaired electron :)

    • 2 years ago
  2. Ruchi. Group Title
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    n=3

    • 2 years ago
  3. Ruchi. Group Title
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    its given that u=1.73

    • 2 years ago
  4. Ruchi. Group Title
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    i m confuse

    • 2 years ago
  5. shivam_bhalla Group Title
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    @Ruchi. \[1.73 = \sqrt{n(n+2)}\] Therefore n = 1 Therefore number of unpaired electron = 1 Now try to finish it off :)

    • 2 years ago
  6. Ruchi. Group Title
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    its answer=[Ar]3d1

    • 2 years ago
  7. Ruchi. Group Title
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    hw u gt n=1

    • 2 years ago
  8. shivam_bhalla Group Title
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    @Ruchi. , substitute n=1 and see in the formula :P

    • 2 years ago
  9. Ruchi. Group Title
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    wait

    • 2 years ago
  10. Ruchi. Group Title
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    1.73 = sqrt(3) = sqrt(n(n+2)) So, n(n+2) = 3 or n = 1 For V, Z = 23, [Ar]4s23d3 am i right.

    • 2 years ago
  11. shivam_bhalla Group Title
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    Yes. @Ruchi, now tell me if Vanadium has 3 unpaired electrons, and you know that the vanadium ion is having 1 unpaired electron, then now can you figure out the charge on vanadium ion :)

    • 2 years ago
  12. Ruchi. Group Title
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    @shivam_bhalla i m nt getting its electrnic configration

    • 2 years ago
  13. Ruchi. Group Title
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    1s2 2s2 2p6 3s2 3p6 4s2 3d3.

    • 2 years ago
  14. shivam_bhalla Group Title
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    @Ruchi. , This question is more intersesting now :P. Let me have a check and let you know the electron configuration.

    • 2 years ago
  15. shivam_bhalla Group Title
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    @Ruchi. Your task is to get a vanadium ion with 1 unpaired electron . Now a simple question to you , first where will you remove the electron from vanadium first ?? s orbital or p orbital ?

    • 2 years ago
  16. Ruchi. Group Title
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    p

    • 2 years ago
  17. shivam_bhalla Group Title
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    Typo ; I meant 3s orbital or 3d orbital ??

    • 2 years ago
  18. Ruchi. Group Title
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    V+4=1S2 2s2 2p6 3s2 3p6 3d1.

    • 2 years ago
  19. Ruchi. Group Title
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    am i right.

    • 2 years ago
  20. Ruchi. Group Title
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    what r u telling i m nt understanding.

    • 2 years ago
  21. shivam_bhalla Group Title
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    Ruchi, The configuration you gave for V4+ is wrong. Think why ?? (tip:check the number of electrons is 4s orbital )

    • 2 years ago
  22. shivam_bhalla Group Title
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    You should always mention 4s 0 while writing the V4+ configuration. So you are partially right @Ruchi.

    • 2 years ago
  23. shivam_bhalla Group Title
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    @Ruchi. V+4=1S2 2s2 2p6 3s2 3p6 4s0 3d1

    • 2 years ago
  24. Ruchi. Group Title
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    0 ka mention torina nakariga.

    • 2 years ago
  25. Ruchi. Group Title
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    kariga

    • 2 years ago
  26. shivam_bhalla Group Title
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    Revise aufbau principle @ruchi. Remove 2 electrons from 4s orbital, then 2 electrons from 3d orbital to get V4+

    • 2 years ago
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