[SOLVED] Here's a neat little combinatorics/graph theory question.
Mr. Smith and his wife invited four other couples for a party. When everyone arrived, some of the people in the room shook hands with some of the others. Of course, nobody shook hands with their spouse and nobody shook hands with the same person twice.
After that, Mr. Smith asked everyone how many times they shook someone’s hand. He received different answers from everybody.
How many times did Mrs. Smith shake someone’s hand?
PS. This took me about 5 minutes to solve when I was presented with it. Can you beat me?

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8 people.

I mean, if four other couples were invited, then 4*2 = 8

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