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viniterranova
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Find the equation of the line tangent to the curve y = 2  (1/3x) ^ 2 which is perpendicular to the line xy = 0.
 2 years ago
 2 years ago
viniterranova Group Title
Find the equation of the line tangent to the curve y = 2  (1/3x) ^ 2 which is perpendicular to the line xy = 0.
 2 years ago
 2 years ago

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viniterranova Group TitleBest ResponseYou've already chosen the best response.0
Correcting in the last line. xy=0.
 2 years ago

integralsabiti Group TitleBest ResponseYou've already chosen the best response.0
The product of the slope of the perpendicular lines is equal to minus 1
 2 years ago

integralsabiti Group TitleBest ResponseYou've already chosen the best response.0
slope for xy=0 is equal to 1
 2 years ago

integralsabiti Group TitleBest ResponseYou've already chosen the best response.0
so the slope of the tangent line would be minus 1
 2 years ago

Chlorophyll Group TitleBest ResponseYou've already chosen the best response.0
Perpendicular slope =  1 y = 2  (1/3x)² = 2  x²/9 >y' = 2x /9 = 1 => x= 4.5, y = 4.75 Thus Tangent line at ( 4.5, 4.75) : y = x .25
 2 years ago

viniterranova Group TitleBest ResponseYou've already chosen the best response.0
Thanks
 2 years ago

viniterranova Group TitleBest ResponseYou've already chosen the best response.0
This is the solution
 2 years ago

Chlorophyll Group TitleBest ResponseYou've already chosen the best response.0
@viniterranova You're unable to post correctly, are you? Let compare these equations from solution and your post: y = (1/3)x² + 2 y = 2  (1/3x) ^ 2
 2 years ago

Chlorophyll Group TitleBest ResponseYou've already chosen the best response.0
Anyway, thanks for pointing out that it's YOUR posting problem :)
 2 years ago
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