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anonymous
 4 years ago
Find the equation of the line tangent to the curve y = 2  (1/3x) ^ 2 which is perpendicular to the line xy = 0.
anonymous
 4 years ago
Find the equation of the line tangent to the curve y = 2  (1/3x) ^ 2 which is perpendicular to the line xy = 0.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Correcting in the last line. xy=0.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The product of the slope of the perpendicular lines is equal to minus 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0slope for xy=0 is equal to 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so the slope of the tangent line would be minus 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Perpendicular slope =  1 y = 2  (1/3x)² = 2  x²/9 >y' = 2x /9 = 1 => x= 4.5, y = 4.75 Thus Tangent line at ( 4.5, 4.75) : y = x .25

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@viniterranova You're unable to post correctly, are you? Let compare these equations from solution and your post: y = (1/3)x² + 2 y = 2  (1/3x) ^ 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Anyway, thanks for pointing out that it's YOUR posting problem :)
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