iloveboys 3 years ago Solve: 0 = 6x^2 - 10x - 4.

1. tim538

you could factor that equation.

2. iloveboys

how

3. DoomDude
4. tim538
5. iloveboys

x+1/3, x=2???

6. iloveboys

x i meant to put x=

7. DoomDude

8. iloveboys

x=-1/3, x=2????

9. iloveboys

is that correct?

10. jim_thompson5910

You can factor, but let's use the quadratic equation to solve this $\Large 0 = 6x^2 - 10x - 4$ $\Large 6x^2 - 10x - 4 = 0$ $\Large x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$ $\Large x = \frac{-(-10)\pm\sqrt{(-10)^2-4(6)(-4)}}{2(6)}$ $\Large x = \frac{10\pm\sqrt{100-(-96)}}{12}$ $\Large x = \frac{10\pm\sqrt{196}}{12}$ $\Large x = \frac{10+\sqrt{196}}{12} \ \text{or} \ x = \frac{10-\sqrt{196}}{12}$ $\Large x = \frac{10+14}{12} \ \text{or} \ x = \frac{10-14}{12}$ $\Large x = \frac{24}{12} \ \text{or} \ x = \frac{-4}{12}$ $\Large x = 2 \ \text{or} \ x = -\frac{1}{3}$ So you are correct iloveboys, nice work

11. iloveboys

thank you

12. DoomDude

13. iloveboys

i have anoion... i have a graph liker this..

14. iloveboys

|dw:1337814199315:dw|the question is what quadratcic* equationis represtenesed below... than the graph

15. iloveboys

its somting l;ike that but more stright and more nice and even

16. iloveboys

answers: Non-factorable Trinomial Difference of Two Squares Not enough information Perfect Square Trinomial

17. jim_thompson5910

since the x intercepts are -2 and 2, we know that x = -2 and x = 2 are zeros So... x = -2 or x = 2 x + 2 = 0 or x - 2 = 0 (x + 2)(x - 2) = 0 x^2 - 4 = 0 Which is a difference of two squares since 4 is 2^2

18. iloveboys

okay thak u.. i was like whatttt.. lol

19. iloveboys

Part 1: Solve each of the quadratic equations below and describe what the solution(s) represent to the graph of each. Show your work to receive full credit. •y = x2 + 3x + 2. •y = x2 + 2x + 1. Part 2: Using complete sentences, answer the following questions about the two quadratic equations above. •Do the two quadratic equations have anything in common? If so, what?. •What makes y = x2 + 3x + 2 different from y = x2 + 2x + 1?.

20. jim_thompson5910

one moment

21. iloveboys

okay sory for all of this

22. jim_thompson5910

no it's fine, just going to type it up elsewhere and copy/paste

23. jim_thompson5910

Part 1 y = x^2 + 3x + 2 0 = x^2 + 3x + 2 x^2 + 3x + 2 = 0 (x+2)(x+1) = 0 x+2=0 or x+1=0 x=-2 or x=-1 So the solutions to y = x^2 + 3x + 2 are x=-2 or x=-1 ------------------------------------------------------- y = x^2 + 2x + 1 0 = x^2 + 2x + 1 x^2 + 2x + 1 = 0 (x+1)^2 = 0 x+1 = 0 x = -1 So the only solution to y = x^2 + 2x + 1 is x = -1

24. jim_thompson5910

let me know when you're ready for part 2

25. iloveboys

i am sorry i was try to understand it got it know go ahead when your ready

26. jim_thompson5910

alright, no worries, take all the time you need and ask about anything

27. iloveboys

thank you i got it know.

28. iloveboys

now

29. iloveboys

30. jim_thompson5910

alright, just checking

31. jim_thompson5910

Part 2 Similarities: The two are similar in that they both are quadratic equations and graph parabolas. The two also open up in the same direction and have the same basic shape. The two quadratics are also factorable. ------------------------------------------------------------------ Differences: y = x^2 + 3x + 2 has 2 solutions or zeros y = x^2 + 2x + 1 has only 1 solution y = x^2 + 3x + 2 intersects the x-axis twice at 2 different spots y = x^2 + 2x + 1 only touches the x-axis at one spot only

32. iloveboys

Solve: x2 - 2x - 24 = 0. Answer x = -4, x = 6 x = 4, x = -6 x = -4, x = -6 x = 4, x = 6

33. jim_thompson5910

I already did this one, did you need to see the steps again?

34. iloveboys

im done for today and im thankful that you helped me so much... hen will you be on gain. and no sorry i didnt post it

35. jim_thompson5910

I should be on tomorrow

36. iloveboys

okay well thank you again!

37. jim_thompson5910

If I'm not on, you can email me or add me on msn or yahoo messenger either one works

38. jim_thompson5910

you're welcome

39. iloveboys

sounds good.. what is your email?

40. jim_thompson5910

jim_thompson5910@hotmail.com

41. iloveboys

ill porbley message you threw yahoo lol not msn lol

42. jim_thompson5910

my messenger screen names are just jim_thompson5910

43. jim_thompson5910

so same name

44. iloveboys

kkkk thank you byee can you repost theanser the question Solve: x2 - 2x - 24 = 0.

45. jim_thompson5910

oh sry, one sec

46. iloveboys

dont be sorry i told u not to.. and than it asked me agiana nd i cant find it lol

47. jim_thompson5910

lol alright, one sec while I type it up

48. iloveboys

ok

49. jim_thompson5910

Use the quadratic formula to solve for x $\Large x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$ $\Large x = \frac{-(-2)\pm\sqrt{(-2)^2-4(1)(-24)}}{2(1)}$ $\Large x = \frac{2\pm\sqrt{4-(-96)}}{2}$ $\Large x = \frac{2\pm\sqrt{100}}{2}$ $\Large x = \frac{2+\sqrt{100}}{2} \ \text{or} \ x = \frac{2-\sqrt{100}}{2}$ $\Large x = \frac{2+10}{2} \ \text{or} \ x = \frac{2-10}{2}$ $\Large x = \frac{12}{2} \ \text{or} \ x = \frac{-8}{2}$ $\Large x = 6 \ \text{or} \ x = -4$ So the answer is choice A

50. iloveboys

thank you jim

51. jim_thompson5910

anytime

52. iloveboys

bye

53. jim_thompson5910

cya later