anonymous
  • anonymous
Solve: 0 = 6x^2 - 10x - 4.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
you could factor that equation.
anonymous
  • anonymous
how
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=0+%3D+6x%5E2+-+10x+-+4

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More answers

anonymous
  • anonymous
http://www.purplemath.com/modules/factquad.htm
anonymous
  • anonymous
x+1/3, x=2???
anonymous
  • anonymous
x i meant to put x=
anonymous
  • anonymous
rewrite that please
anonymous
  • anonymous
x=-1/3, x=2????
anonymous
  • anonymous
is that correct?
jim_thompson5910
  • jim_thompson5910
You can factor, but let's use the quadratic equation to solve this \[\Large 0 = 6x^2 - 10x - 4\] \[\Large 6x^2 - 10x - 4 = 0\] \[\Large x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\] \[\Large x = \frac{-(-10)\pm\sqrt{(-10)^2-4(6)(-4)}}{2(6)}\] \[\Large x = \frac{10\pm\sqrt{100-(-96)}}{12}\] \[\Large x = \frac{10\pm\sqrt{196}}{12}\] \[\Large x = \frac{10+\sqrt{196}}{12} \ \text{or} \ x = \frac{10-\sqrt{196}}{12}\] \[\Large x = \frac{10+14}{12} \ \text{or} \ x = \frac{10-14}{12}\] \[\Large x = \frac{24}{12} \ \text{or} \ x = \frac{-4}{12}\] \[\Large x = 2 \ \text{or} \ x = -\frac{1}{3}\] So you are correct iloveboys, nice work
anonymous
  • anonymous
thank you
anonymous
  • anonymous
great answer man! provs
anonymous
  • anonymous
i have anoion... i have a graph liker this..
anonymous
  • anonymous
|dw:1337814199315:dw|the question is what quadratcic* equationis represtenesed below... than the graph
anonymous
  • anonymous
its somting l;ike that but more stright and more nice and even
anonymous
  • anonymous
answers: Non-factorable Trinomial Difference of Two Squares Not enough information Perfect Square Trinomial
jim_thompson5910
  • jim_thompson5910
since the x intercepts are -2 and 2, we know that x = -2 and x = 2 are zeros So... x = -2 or x = 2 x + 2 = 0 or x - 2 = 0 (x + 2)(x - 2) = 0 x^2 - 4 = 0 Which is a difference of two squares since 4 is 2^2
anonymous
  • anonymous
okay thak u.. i was like whatttt.. lol
anonymous
  • anonymous
Part 1: Solve each of the quadratic equations below and describe what the solution(s) represent to the graph of each. Show your work to receive full credit. •y = x2 + 3x + 2. •y = x2 + 2x + 1. Part 2: Using complete sentences, answer the following questions about the two quadratic equations above. •Do the two quadratic equations have anything in common? If so, what?. •What makes y = x2 + 3x + 2 different from y = x2 + 2x + 1?.
jim_thompson5910
  • jim_thompson5910
one moment
anonymous
  • anonymous
okay sory for all of this
jim_thompson5910
  • jim_thompson5910
no it's fine, just going to type it up elsewhere and copy/paste
jim_thompson5910
  • jim_thompson5910
Part 1 y = x^2 + 3x + 2 0 = x^2 + 3x + 2 x^2 + 3x + 2 = 0 (x+2)(x+1) = 0 x+2=0 or x+1=0 x=-2 or x=-1 So the solutions to y = x^2 + 3x + 2 are x=-2 or x=-1 ------------------------------------------------------- y = x^2 + 2x + 1 0 = x^2 + 2x + 1 x^2 + 2x + 1 = 0 (x+1)^2 = 0 x+1 = 0 x = -1 So the only solution to y = x^2 + 2x + 1 is x = -1
jim_thompson5910
  • jim_thompson5910
let me know when you're ready for part 2
anonymous
  • anonymous
i am sorry i was try to understand it got it know go ahead when your ready
jim_thompson5910
  • jim_thompson5910
alright, no worries, take all the time you need and ask about anything
anonymous
  • anonymous
thank you i got it know.
anonymous
  • anonymous
now
anonymous
  • anonymous
go ahead
jim_thompson5910
  • jim_thompson5910
alright, just checking
jim_thompson5910
  • jim_thompson5910
Part 2 Similarities: The two are similar in that they both are quadratic equations and graph parabolas. The two also open up in the same direction and have the same basic shape. The two quadratics are also factorable. ------------------------------------------------------------------ Differences: y = x^2 + 3x + 2 has 2 solutions or zeros y = x^2 + 2x + 1 has only 1 solution y = x^2 + 3x + 2 intersects the x-axis twice at 2 different spots y = x^2 + 2x + 1 only touches the x-axis at one spot only
anonymous
  • anonymous
Solve: x2 - 2x - 24 = 0. Answer x = -4, x = 6 x = 4, x = -6 x = -4, x = -6 x = 4, x = 6
jim_thompson5910
  • jim_thompson5910
I already did this one, did you need to see the steps again?
anonymous
  • anonymous
im done for today and im thankful that you helped me so much... hen will you be on gain. and no sorry i didnt post it
jim_thompson5910
  • jim_thompson5910
I should be on tomorrow
anonymous
  • anonymous
okay well thank you again!
jim_thompson5910
  • jim_thompson5910
If I'm not on, you can email me or add me on msn or yahoo messenger either one works
jim_thompson5910
  • jim_thompson5910
you're welcome
anonymous
  • anonymous
sounds good.. what is your email?
jim_thompson5910
  • jim_thompson5910
anonymous
  • anonymous
ill porbley message you threw yahoo lol not msn lol
jim_thompson5910
  • jim_thompson5910
my messenger screen names are just jim_thompson5910
jim_thompson5910
  • jim_thompson5910
so same name
anonymous
  • anonymous
kkkk thank you byee can you repost theanser the question Solve: x2 - 2x - 24 = 0.
jim_thompson5910
  • jim_thompson5910
oh sry, one sec
anonymous
  • anonymous
dont be sorry i told u not to.. and than it asked me agiana nd i cant find it lol
jim_thompson5910
  • jim_thompson5910
lol alright, one sec while I type it up
anonymous
  • anonymous
ok
jim_thompson5910
  • jim_thompson5910
Use the quadratic formula to solve for x \[\Large x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\] \[\Large x = \frac{-(-2)\pm\sqrt{(-2)^2-4(1)(-24)}}{2(1)}\] \[\Large x = \frac{2\pm\sqrt{4-(-96)}}{2}\] \[\Large x = \frac{2\pm\sqrt{100}}{2}\] \[\Large x = \frac{2+\sqrt{100}}{2} \ \text{or} \ x = \frac{2-\sqrt{100}}{2}\] \[\Large x = \frac{2+10}{2} \ \text{or} \ x = \frac{2-10}{2}\] \[\Large x = \frac{12}{2} \ \text{or} \ x = \frac{-8}{2}\] \[\Large x = 6 \ \text{or} \ x = -4\] So the answer is choice A
anonymous
  • anonymous
thank you jim
jim_thompson5910
  • jim_thompson5910
anytime
anonymous
  • anonymous
bye
jim_thompson5910
  • jim_thompson5910
cya later

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