The equation of a hyperbola is given by: 25x^2-16y^2+100x+96y=144 Rewrite the equation in standard form

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The equation of a hyperbola is given by: 25x^2-16y^2+100x+96y=144 Rewrite the equation in standard form

Mathematics
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ok.. it's complete the square time.. |dw:1337817367153:dw|
do you what you need in that first parenthesis to make it into a perfect square trinomial?
Yes, I do. It would be 4 in the first parenthesis and 9 in the second, correct? I am confused on what to do after that because the number on the other side of the equal sign is actually 444

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Other answers:

yes... you're correct
whatever you do to one side, you do to the other.... |dw:1337817614794:dw|
Yes, and then I get 400 on the right side and I'm unsure how to apply that to the other side.
|dw:1337817875892:dw|
|dw:1337817783416:dw|
|dw:1337817942410:dw|
oh... you're way ahead of me... :)
Is that right though? Is there anyway I can check the process because sometimes I keep going and it turns out wrong?
shouldn't the right side be 100?
|dw:1337818132008:dw|
144 is actually 444. I typed it in wrong originally and then explained it after
ooh ok, so the right side is 400..
the process is correct... if there are no calculation errors, the equation is correct.
the equation you ended up with...
|dw:1337818278093:dw|
yes.. do you know where the center is?
It would be (-2, -3) right? And its horizontal? How can I tell..I'm confused on when its different? Is a just always bigger?
wait...
this should be negative.... right? |dw:1337818435775:dw|
Yes. Darn it. I should have seen that. Thank you
here's your verification : center is at (-2, 3) http://www.wolframalpha.com/input/?i=center+25x%5E2-16y%5E2%2B100x%2B96y%3D144
Thank you! That's perfect! The equation is horizontal right?
equation?
oh... yes.. this is a horizontal or left/right branch hyperbola...
good work...
And so a would be 4? Because in standard form it is 16 which is a^2?
yes... a=4 b= c=
b=5 and c= the square root of 41?

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