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ok.. it's complete the square time..
|dw:1337817367153:dw|

do you what you need in that first parenthesis to make it into a perfect square trinomial?

yes... you're correct

whatever you do to one side, you do to the other....
|dw:1337817614794:dw|

Yes, and then I get 400 on the right side and I'm unsure how to apply that to the other side.

|dw:1337817875892:dw|

|dw:1337817783416:dw|

|dw:1337817942410:dw|

oh... you're way ahead of me... :)

shouldn't the right side be 100?

|dw:1337818132008:dw|

144 is actually 444. I typed it in wrong originally and then explained it after

ooh ok, so the right side is 400..

the process is correct... if there are no calculation errors, the equation is correct.

the equation you ended up with...

|dw:1337818278093:dw|

yes.. do you know where the center is?

wait...

this should be negative.... right?
|dw:1337818435775:dw|

Yes. Darn it. I should have seen that.
Thank you

Thank you! That's perfect! The equation is horizontal right?

equation?

oh... yes.. this is a horizontal or left/right branch hyperbola...

good work...

And so a would be 4? Because in standard form it is 16 which is a^2?

yes...
a=4
b=
c=

b=5 and c= the square root of 41?