ERoseM
The equation of a hyperbola is given by: 25x^2-16y^2+100x+96y=144
Rewrite the equation in standard form
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dpaInc
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ok.. it's complete the square time..
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dpaInc
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do you what you need in that first parenthesis to make it into a perfect square trinomial?
ERoseM
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Yes, I do. It would be 4 in the first parenthesis and 9 in the second, correct? I am confused on what to do after that because the number on the other side of the equal sign is actually 444
dpaInc
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yes... you're correct
dpaInc
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whatever you do to one side, you do to the other....
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ERoseM
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Yes, and then I get 400 on the right side and I'm unsure how to apply that to the other side.
dpaInc
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|dw:1337817875892:dw|
ERoseM
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|dw:1337817783416:dw|
dpaInc
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dpaInc
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oh... you're way ahead of me... :)
ERoseM
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Is that right though? Is there anyway I can check the process because sometimes I keep going and it turns out wrong?
dpaInc
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shouldn't the right side be 100?
dpaInc
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|dw:1337818132008:dw|
ERoseM
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144 is actually 444. I typed it in wrong originally and then explained it after
dpaInc
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ooh ok, so the right side is 400..
dpaInc
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the process is correct... if there are no calculation errors, the equation is correct.
dpaInc
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the equation you ended up with...
ERoseM
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dpaInc
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yes.. do you know where the center is?
ERoseM
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It would be (-2, -3) right? And its horizontal? How can I tell..I'm confused on when its different? Is a just always bigger?
dpaInc
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wait...
dpaInc
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this should be negative.... right?
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ERoseM
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Yes. Darn it. I should have seen that.
Thank you
ERoseM
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Thank you! That's perfect! The equation is horizontal right?
dpaInc
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equation?
dpaInc
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oh... yes.. this is a horizontal or left/right branch hyperbola...
dpaInc
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good work...
ERoseM
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And so a would be 4? Because in standard form it is 16 which is a^2?
dpaInc
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yes...
a=4
b=
c=
ERoseM
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b=5 and c= the square root of 41?