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In the figure below, the right circular cone has a radius of 2 and height of 2 square root of 3. Find the lateral area.
The equation for lateral area is: 1/2 [( Pi x D) x Slant height) where D is diameter. We need to then find the slant height of the cone, which is a right triangle. \[2^2+(2\sqrt3)^2=L^2\] L= 4 So \[.5*(\pi*2)*4=A\] A=12.56
the answer choices are 8pi \[4\sqrt{3}\]\[8\sqrt{3}\]pi (this is after 8 square root of 3) and \[8\sqrt{3}\] pi over 3.