The area of a regular hexagon is 35 in^2. What is the length of one side.
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
A regular hexagon is made up of 6 trangles with vertex angles of 60 degrees. Each triangle will have an area of 35/6 in^2 and will be equilateral. Each of those triangles can be split into two right triangles. The angles of those right triangles would be 30, 60, 90 degrees and the areas of theses right triangles would be 35/12 in^2 which equals 0.5 *base* height. For a right triangle made out of an equilateral triangle, the base would be 1/2 the hypotnuse. Therefore the equation for the right triangle would be hyp^2 = b^2 + h^2. Substituting that we know we can right it as follows:
2(b)^2= b^2= (70/12b)^2 where h (the height)= (35/12) *2/b=70/12b
4b^2=b^2= (4900/144b^2) since b =0.5s
S^2= S^4/4 + (4900/36)
S^4= 19600/108= 181.5
Sorry for the last answer my little sister did that :)