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Connie1 Group Title

What is the exluded values of the following functions? 1. y = 4/(9x - 45) 2. y = 7/(2x + 48)

  • 2 years ago
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  1. juan_9292 Group Title
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    excluded values are like holes on a function or graph. which tend to happen when the denominator equals to 0

    • 2 years ago
  2. ParthKohli Group Title
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    You get the excluded value when you get 0 as the denominator. First one- \(\Large \color{MidnightBlue}{\Rightarrow 9x - 45 = 0 }\) Solve for x to get the excluded value. Same for second.

    • 2 years ago
  3. ParthKohli Group Title
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    \(\Large \color{MidnightBlue}{\Rightarrow 2x + 48 = 0 }\) Here's for the second

    • 2 years ago
  4. shivam_bhalla Group Title
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    The value of denominator should not be equal to zero as the value of function would become infinity. Therefore 9x−45=0 -->The value that x should not be equal to

    • 2 years ago
  5. Connie1 Group Title
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    0 is not an answer choice.

    • 2 years ago
  6. ParthKohli Group Title
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    Solve for x in the equations I have given.

    • 2 years ago
  7. ParthKohli Group Title
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    \(\Large \color{MidnightBlue}{\Rightarrow 9x = 45 }\) \(\Large \color{MidnightBlue}{\Rightarrow x = 5 }\) Therefor, excluded value in the first one is 5.

    • 2 years ago
  8. juan_9292 Group Title
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    right, but what we mean is that to find the excluded values you need to set the denominator to 0. for example the first problem just taking the denominator into consideration since its what we are looking at 9x+45=0 9x=-45 x=-45/9

    • 2 years ago
  9. juan_9292 Group Title
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    *** sorry, @ParthKohli is right, I had my number wrong should be 9x-45 which will change the sign to positive. sorry about that

    • 2 years ago
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