Write the expression as a single natural logarithm. 3 ln 3 + 3 ln c

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Write the expression as a single natural logarithm. 3 ln 3 + 3 ln c

Mathematics
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factor out 3 3(ln 3 + ln c)
can you do the rest?
Use the following properrties: \[\large a \ln (b) = \ln (b^a)\] \[\ln a + \ln b = \ln (ab)\]

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You can write \[3 \ln(3) = \ln(3^3)\] \[3 \ln(c) = \ln(c^3)\] So you get \[\ln(3^3)+\ln(c^3)\] Now use the second property which I gave in my previous comment
soo...\[\ln9c^3\]
^that's right
Wrong. 3^3 = 27
you might wanna do a parenthesis though \[\large \ln (27c^3)\] and should be 27 lol
:o ohh i see, hah oops thanksssss
np :)

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