Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
← 55 members online
 0 viewing

This Question is Closed

shivam_bhallaBest ResponseYou've already chosen the best response.1
First take 5t = p 5dt = dp
 one year ago

gmerBest ResponseYou've already chosen the best response.0
\[{1 \over 5} \int {te^p \over (p 1)^2}dp\]
 one year ago

shivam_bhallaBest ResponseYou've already chosen the best response.1
you get \[\large \frac{1}{5^2}\int\limits_{}^{}\frac{pe^p}{(p+1)^2}dp\] \[\large \frac{1}{2*5^2}\int\limits_{}^{}\frac{(2p+2)e^p}{(p^2+1+2p)}dp  \large \frac{1}{5^2}\int\limits_{}^{}\frac{e^p}{(p+1)^2}dp\]
 one year ago

shivam_bhallaBest ResponseYou've already chosen the best response.1
@gmer, got it ??
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.