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puffslotion28

  • 3 years ago

Convert the complex number 3 - 3i into its polar representation. a. 3(cos(60degrees) + isin(60degrees)) b. 3√2(cos(135degrees) + isin(135degrees)) c. √3(cos(225degrees) + isin(225degrees)) d. 3√(cos(315degrees) + isin(315degrees))

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  1. shivam_bhalla
    • 3 years ago
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    Polar representation of any complex number is given by \[z = |z| (\cos (\theta)+i \sin(\theta))\]

  2. dumbcow
    • 3 years ago
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    For a complex number a+bi the magnitude is found by sqrt(a^2 +b^2) the angle is found by tan(theta) = b/a

  3. shivam_bhalla
    • 3 years ago
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    As dumbcow said above |z|-->Magnitude θ-->angle

  4. puffslotion28
    • 3 years ago
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    so the answer is b. 3√2(cos(135degrees) + isin(135degrees))?

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